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Bingel [31]
3 years ago
6

Why are only certain colors absorbed by and emitted from an atom?

Chemistry
1 answer:
zavuch27 [327]3 years ago
6 0
The way I would explain it is quite difficult to understand, so this is what Google says. "The wavelength (or equivalently, frequency) of the photon is determined by the difference in energy between the two states. These emitted photons form the element's spectrum. The fact that only certain colors appear in an element's atomic emission spectrum means that only certain frequencies of light are emitted." I hope this helped.
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How would a solution that is labeled 5.0 M would be read as?
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5 moles because molarity signifies number of moles dissolved in One litre of water
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2Na(s) + Cl2(g) - 2NaCl(s) + 822 kj
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Is there any other part to this question? If not I'm pretty sure the answer is 205.5 kJ

Explanation:

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2 years ago
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Woodpeckers find insects to eat by pecking holes in trees with their beaks. One day, a woodpecker finds a particular tree that o
bixtya [17]

Answer:

1. Reflex Conditioning

Explanation:

Conditioning is an aspect of learning where a stimulus works effectively in producing a response from an organism. This response becomes regular given the type of reinforcement that is administered to the organism. The reinforcement is usually a reward that is given to the organism.

This is what is observed in the woodpecker.  The stimulus or reinforcement which proves effective in producing a continuous response  from the woodpecker is the abundant supply of the birds favorite bugs. This reinforcement makes it possible for the woodpecker to become conditioned towards returning to the tree.

4 0
3 years ago
15.1 L N2 at 25 °C and 125 kPa and 44.3 L O2 at 25 °C and 125 kPa were transferred to a tank with a volume of 6.25 L. What is th
Y_Kistochka [10]

Answer:

The total pressure of the mixture in the tank of volume 6.25 litres at 51°C  is 1291.85 kPa.

Explanation:

For N2,

                Pressure(P₁)=125 kPa

                  Volume(V₁)=15·1 L

                Temperature (T₁)=25°C=25+273 K=298 K

Similarly, for Oxygen,

                   Pressure(P₂)= 125 kPa

                   Volume(V₂)= 44.3 L

                  Temperature(T₂)=25°C= 298 K

Then, for the mixture,

              Volumeof the mixture( V)= 6.25 L

                                     Pressure(P)=?

                Temperature (T)= 51°C = 51+273 K=324 K

Then, By Combined gas laws,

                                 \frac{P_{1} V_{1} }{T_{1} } +\frac{P_{2} V_{2} }{T_{2} } =\frac{PV}{T}

                      or, \frac{15.1*125}{298} +\frac{44.3*125}{298} =\frac{P*6.25}{324}

                     or, 6.34+18.58=\frac{P*6.25}{324}

                     or, P=\frac{24.92*324}{6.25}

                        ∴P=1291.85 kPa

So the total pressure of the mixture in the tank of volume 6.25 litres at 51°C  is 1291.85 kPa.

3 0
3 years ago
A student carefully drops a 9.0 g solid Zn pellet initially at 50.0°C into an insulated cup containing 30.0 g of water at 27.8°C
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Answer: choice B

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3 years ago
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