1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bazaltina [42]
2 years ago
7

Using the periodic table to locate each element, write the electron configuration of(a) Ru;

Chemistry
1 answer:
Dimas [21]2 years ago
4 0

Ruthenium is a chemical element with the symbol Ru and atomic number 44. The electron configuration of Ru is 5s14d^{7}.

<h3>How to write an electronic configuration?</h3>
  • Find the supplied element's atomic number on the periodic table and identify it.
  • The energy level and kind of orbital should be listed first, followed by the number of electrons in the orbital in superscript.
  • The Aufbau principle's diagonal rule for electron filling order in the various subshells is the simplest way to express the electronic configuration of any element.
  • The Aufbau rule, the Pauli-exclusion rule, and Hund's Rule are the three rules that must be followed when expressing the electron configuration in the orbital box diagram.

Ruthenium exists a chemical element with the symbol Ru and atomic number 44. The electron configuration of Ru is 5s14d^{7}.

<h3></h3>

To learn more about electronic configuration, refer to:

brainly.com/question/11316046

#SPJ4

You might be interested in
1. How are electromagnets similar to other magnets?
Tju [1.3M]

Answer:a As the name suggests, a permanent magnet is 'permanent'. ... An electromagnet is made from a coil of wire which acts as a magnet when an electric current passes through it. Often an electromagnet is wrapped around a core of ferromagnetic material like steel, which enhances the magnetic field produced by the coil.... hope these helps chu :/

Explanation:

8 0
2 years ago
You are required to prepare 500 ml of a 6.00 M solution of HNO3 from a stock solution of 12.0 M. Describe in detail how you woul
andriy [413]

Answer: 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.

Explanation:

According to the dilution law,

C_1V_1=C_2V_2

where,

C_1 = concentration of stock solution = 12.0 M

V_1 = volume of stock solution = ?

C_2 = concentration of diluted solution= 6.00 M

V_2 = volume of diluted acid solution = 500 ml

Putting in the values we get:

12.0\times V_1=6.00\times 500

V_1=250ml

Thus 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.

8 0
3 years ago
1. Chemical equilibrium is established when the number of reactants equals the number of products.. . - True. - False. . 2. Acco
torisob [31]
<span>1)false a in chemical equilibrium concentration of reactant is equal to concentration of product
 2)as here they said heat is added in product side means its endothermic reaction and in endothermic reaction on increasing temp. equilibrium shift towards forward direction so its true
 3) B)as here mole are equal in reactant and product side that is 2 and if we increase pressure equilibrium shift in dat direction where no. of moles are less and here mole are equal so it will remain unaffected</span>
7 0
3 years ago
Read 2 more answers
Name a property copper has?
Ilya [14]

Answer:

Explanation:

It is malleable, ductile, and a good conductor of electricity and heat.

4 0
2 years ago
S8 + 24 F2 ⟶ 8 SF6
Arturiano [62]

Answer:

Theoretical Yield of SF₆ = 2.01 moles

Explanation: If you understand and can apply the methodology below, you will find it applies to ALL chemical reaction stoichiometry problems based on the balanced standard equation; i.e., balanced to smallest whole number coefficients.

Solution 1:

Rule => Convert given mass values to moles, solve problem using coefficient ratios. Finish by converting moles to the objective dimensions.

Given      S₈            +          24F₂            =>    8SF₆

             425g                    229g                      ?

= 425g/256g/mol.      = 226g/38g/mol.

= 1.66 moles S₈          = 6.03 moles F₂ <= Limiting Reactant

<em>Determining Limiting Reactant => Divide moles each reactant by their respective coefficient; the smaller value will always be the limiting reactant. </em>

S₈ = 1.66/1 = 1.66

F₂ = 6.03/24 = 0.25 => F₂ is the limiting reactant

<em>Determining Theoretical Yield:</em>

Note: When working problem do not use the division ratio results for determining limiting reactant. Use the moles F₂ calculated from 229 grams F₂ => 6.03 moles F₂. The division procedure to define the smaller value and limiting reactant is just a quick way to find which reactant controls the extent of reaction.  

Given      S₈            +          24F₂            =>    8SF₆

             425g                    229g                      ?

   = 425g/256g/mol. = 226g/38g/mol.

= 1.66 moles S₈          = 6.03 moles F₂ <= Limiting Reactant

<em>Max #moles SF₆ produced from 6.03 moles F₂ and an excess S₈ </em>

Since coefficient values represent moles, the reaction ratio for the above reaction is 24 moles F₂ to 8 moles SF₆. Such implies that the moles of SF₆ (theoretical) calculated from 6.03 moles of F₂ must be a number less than the 6.03 moles F₂ given. This can be calculated by using a ratio of equation coefficients between 24F₂ and 8SF₆  to make the outcome smaller than 6.03. That is,

moles SF₆ = 8/24 x 6.03 moles = 2.01 moles SF₆ (=> theoretical yield)  

S₈ + 24F₂ => 8SF₆

moles SF₆ = 8/24(6.03) moles = 2.01 moles

You would NOT want to use 24/8(6.03) = 18.1 moles which is a value >> 6.03.        

This analysis works for all reaction stoichiometry problems.

Convert to moles => divide by coefficients for LR => solve by mole mole ratios from balanced reaction and moles of given.    

____________________

Here's another example just for grins ...

             C₂H₆O   +   3O₂     =>     2CO₂    + 3H₂O

Given:    253g          307g               ?               ?

a. Determine Limiting Reactant

b. Determine mass in grams of CO₂ & H₂O produced        

Limiting Reactant

moles  C₂H₆O = 253g/46g/mol = 5.5 moles  => 5.5/1 = 5.5

moles  O₂ = 307g/32g/mol = 9.6 moles         =><em>  9.6/24 = 0.4 ∴ O₂ is L.R.</em>

But the problem is worked using the mole values; NOT the number results used to ID the limiting reactant.  

 C₂H₆O   +       3O₂          =>     2CO₂    + 3H₂O

------------ 9.6 mole (L.R.)              ?               ?

mole yield CO₂ = 2/3(9.6)mole = 6.4 mole  (CO₂ coefficient < O₂ coefficient)

mole yield H₂O = 9.6mole  = 9.6mole (coefficients O₂ & CO₂ are same.)

mole used C₂H₆O = 1/3(9.6)mole = 3.2 mole (coefficient  C₂H₆O < coefficient O₂)

For grams => moles x formula weight (g/mole)

7 0
3 years ago
Other questions:
  • Calculate the pH of a buffer prepared by mixing 20.0 mL of 0.10 M acetic acid and 55.0 mL of 0.10 M sodium acetate
    9·1 answer
  • Explain how a light ray behaves when it strikes a mirror?
    11·2 answers
  • Which statements about mixture is FALSE?
    13·1 answer
  • 2 Nobr +heat &gt; 2 no2+br2 what happens when you remove nobr
    13·1 answer
  • A warm front moves into a region. What kind of weather most likely results?
    7·2 answers
  • What happens when a substance undergoes a physical change?
    10·2 answers
  • what happens to the particles in a gas when the temperature increases? How does this affect the pressure of the gas?
    6·2 answers
  • How many grams of sodium metal must be introduced to water to produce 3.3 grams of hydrogen gas?
    5·1 answer
  • What is an atomic number? An atomic mass?
    8·2 answers
  • An aqueous solution of potassium hydroxide is standardized by titration with a 0.167 M solution of nitric acid. If 16.6 mL of ba
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!