Using the periodic table to locate each element, write the electron configuration of(a) Ru;

1 answer:

4 0

Ruthenium is a chemical element with the symbol Ru and atomic number 44. The electron configuration of Ru is $5s14d^{7}$ .

<h3>How to write an electronic configuration?</h3>

Find the supplied element's atomic number on the periodic table and identify it.
The energy level and kind of orbital should be listed first, followed by the number of electrons in the orbital in superscript.
The Aufbau principle's diagonal rule for electron filling order in the various subshells is the simplest way to express the electronic configuration of any element.
The Aufbau rule, the Pauli-exclusion rule, and Hund's Rule are the three rules that must be followed when expressing the electron configuration in the orbital box diagram.

Ruthenium exists a chemical element with the symbol Ru and atomic number 44. The electron configuration of Ru is $5s14d^{7}$ .

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Answer:

$\boxed {\boxed {\sf 0.80 \ mol\ F}}$

Explanation:

We are asked to find how many moles are in 4.8 × 10²³ fluorine atoms. We convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of fluorine.

We will convert using dimensional analysis and set up a ratio using Avogadro's Number.

$\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}$

We are converting 4.8 × 10²³ fluorine atoms to moles, so we multiply the ratio by this number.

$4.8 \times 10^{23} \ atoms \ F *\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}$

Flip the ratio so the units of atoms of fluorine cancel each other out.

$4.8 \times 10^{23} \ atoms \ F *\frac { 1 \ mol \ F}{6.022 \times 10^{23} \ atoms \ F}$

$4.8 \times 10^{23} *\frac { 1 \ mol \ F}{6.022 \times 10^{23} }$

Condense into 1 fraction.

$\frac { 4.8 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ F$

Divide.

$0.7970773829 \ mol \ F$

The original measurement of atoms has 2 significant figures, so our answer must have the same. For the number we found, that is the hundredths place. The 7 in the thousandths tells us to round the 9 in the hundredths place up to a 0. Then, we also have to round the 7 in the tenths place up to an 8.

$0.80 \ mol \ F$