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bazaltina [42]
2 years ago
7

Using the periodic table to locate each element, write the electron configuration of(a) Ru;

Chemistry
1 answer:
Dimas [21]2 years ago
4 0

Ruthenium is a chemical element with the symbol Ru and atomic number 44. The electron configuration of Ru is 5s14d^{7}.

<h3>How to write an electronic configuration?</h3>
  • Find the supplied element's atomic number on the periodic table and identify it.
  • The energy level and kind of orbital should be listed first, followed by the number of electrons in the orbital in superscript.
  • The Aufbau principle's diagonal rule for electron filling order in the various subshells is the simplest way to express the electronic configuration of any element.
  • The Aufbau rule, the Pauli-exclusion rule, and Hund's Rule are the three rules that must be followed when expressing the electron configuration in the orbital box diagram.

Ruthenium exists a chemical element with the symbol Ru and atomic number 44. The electron configuration of Ru is 5s14d^{7}.

<h3></h3>

To learn more about electronic configuration, refer to:

brainly.com/question/11316046

#SPJ4

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(a) Calculate the wavelength of light in vacuum that has a frequency of 5.49 ✕ 1018 Hz. 0.0546 Correct: Your answer is correct.
vfiekz [6]

Answer:

a) Wavelength of the light in vacuum = (5.46 × 10⁻¹¹) m = 0.0546 nm

b) Wavelength of the light in diamond = (2.26 × 10⁻¹¹) m = 0.0226 nm

c) Energy of one photon in vacuum = (3.638 × 10⁻¹⁵) J = (2.271 × 10⁴) eV

d) No, the energy of the photon doesn't change when it is travelling inside diamond.

Explanation:

Wavelength (λ), frequency (f) and velocity of light (v) are related as thus

v = fλ

a) v = fλ

v = velocity of light in vacuum = (3.0 × 10⁸) m/s

f = frequency of the light = (5.49 × 10¹⁸) Hz

λ = wavelength of the light = ?

λ = (v/f) = (3.0 × 10⁸) ÷ (5.49 × 10¹⁸)

= (5.46 × 10⁻¹¹) m = 0.0546 nm

b) To find the wavelength of the light in diamond, we need the refractive index of diamond. This is because light, just like all other waves, change their velocities and subsequently their wavelengths in different materials according to the refractive index of the materials.

Refractive index of diamond = 2.42 (from literature)

2.42 = (wavelength of light in vacuum) ÷ (wavelength of light in diamond)

2.42 = 0.0546 ÷ λ

λ = 0.0546 ÷ 2.42 = 0.0226 nm

c) Energy of a photon in vacuum is given as

E = hf

where E = energy in Joules = ?

h = Planck's constant = (6.626 × 10⁻³⁴) J.s

f = frequency of the light in vacuum = (5.49 × 10¹⁸) Hz

E = (6.626 × 10⁻³⁴) × (5.49 × 10¹⁸) = (3.638 × 10⁻¹⁵) J

1 eV = (1.602 × 10⁻¹⁹) J

The amount of the calculated energy in eV

= (3.638 × 10⁻¹⁵) ÷ (1.602 × 10⁻¹⁹) = (2.271 × 10⁴) eV

d) As light travels from material to material, it's velocity and wavelength changes from material to material, but the frequency of the light waves stay the same. Since the energy of the photon depends solely on this frequency, it shows that the energy of the photon stays consistent in whichever material.

Hope this Helps!!!

3 0
3 years ago
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