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bazaltina [42]
2 years ago
7

Using the periodic table to locate each element, write the electron configuration of(a) Ru;

Chemistry
1 answer:
Dimas [21]2 years ago
4 0

Ruthenium is a chemical element with the symbol Ru and atomic number 44. The electron configuration of Ru is 5s14d^{7}.

<h3>How to write an electronic configuration?</h3>
  • Find the supplied element's atomic number on the periodic table and identify it.
  • The energy level and kind of orbital should be listed first, followed by the number of electrons in the orbital in superscript.
  • The Aufbau principle's diagonal rule for electron filling order in the various subshells is the simplest way to express the electronic configuration of any element.
  • The Aufbau rule, the Pauli-exclusion rule, and Hund's Rule are the three rules that must be followed when expressing the electron configuration in the orbital box diagram.

Ruthenium exists a chemical element with the symbol Ru and atomic number 44. The electron configuration of Ru is 5s14d^{7}.

<h3></h3>

To learn more about electronic configuration, refer to:

brainly.com/question/11316046

#SPJ4

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The vapor pressure of water at 65oC is 187.54 mmHg. What is the vapor pressure of a ethylene glycol (CH2(OH)CH2(OH)) solution ma
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Answer:

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

Explanation:

Vapor pressure of water at 65 °C=p_o= 187.54 mmHg

Vapor pressure of the solution at 65 °C= p_s

The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.

Mass of ethylene glycol = 22.37 g

Mass of water in a solution = 82.21 g

Moles of water=n_1=\frac{82.21 g}{18 g/mol}=4.5672 mol

Moles of ethylene glycol=n_2=\frac{22.37 g}{62.07 g/mol}=0.3603 mol

\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}

\frac{187.54 mmHg-p_s}{187.54 mmHg}=\frac{0.3603 mol}{0.3603 mol+4.5672 mol}

p_s=173.83 mmHg

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

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