Which of the following is an example of a chemical change?

Bess [88]

All of the above (#4)

5 0

3 years ago

The specific heat of liquid bromine is 0.226 J/g-K. How much heat (J) is required to raise the temperature of 10.0 mL of bromine

Viefleur [7K]

Answer:

16.2 J

Explanation:

Step 1: Given data

Specific heat of liquid bromine (c): 0.226 J/g.K

Volume of bromine (V): 10.0 mL

Initial temperature: 25.00 °C

Final temperature: 27.30 °C

Density of bromine (ρ): 3.12 g/mL

Step 2: Calculate the mass of bromine

The density is equal to the mass divided by the volume.

ρ = m/V

m = ρ × V

m = 3.12 g/mL × 10.0 mL

m = 31.2 g

Step 3: Calculate the change in the temperature (ΔT)

ΔT = 27.30 °C - 25.00 °C = 2.30 °C

The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.

Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine

We will use the following expression.

Q = c × m × ΔT

Q = 0.226 J/g.K × 31.2 g × 2.30 K

Q = 16.2 J

7 0

3 years ago

Which statement about the scientific veiws is correct?

hammer [34]

I think the answer will be b cuh

4 0

4 years ago

How many grams of barium chloride are produced when 1.25 x 1023 molecules of HCl reacts with barium?

sp2606 [1]

Considering the reaction stoichiometry and Avogadro's Number, the mass of barium chloride produced is 21.6 grams.

<h2>Balanced reaction</h2>

The balanced reaction is

2 HCl + Ba → BaCl₂ + H₂

<h2>Moles of HCl that react</h2>

Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of HCl, then 1.25×10²³ molecules are contained in how many moles of HCl?

amount of moles of HCl= (1.25×10²³ molecules × 1 mole)÷ 6.023×10²³ atoms

<u><em>amount of moles of HCl= 0.2075 moles</em></u>

Then, 0.2075 moles of HCl react.

<h2>Reaction stoichiometry</h2>

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

HCl: 2 moles
Ba: 1 mole
BaCl₂: 1 mole
H₂: 1 mole

<h2>Mass of barium chloride produced</h2>

Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl produce 1 mole of BaCl₂, 0.2075 moles of HCl will produce how many moles of BaCl₂?

$amount of moles of BaCl_{2} =\frac{0.2075 moles of HCl x 1 mole of BaCl_{2} }{ 2moles of HCl}$

<u><em>amount of moles of BaCl₂= 0.10375 moles</em></u>

Being the molar mass of BaCl₂ 208.24 g/mole, then the mass of barium chloride produced is calculated as:

$0.10375 molesx\frac{208.24 grams}{1 mole} =21.6 grams$

Finally, the mass of barium chloride produced is 21.6 grams.

Learn more about:

Avogadro's Number

Reaction stoichiometry

7 0

3 years ago

If a thimble holds 5 mi of water, how many liters can it hold

Mashcka [7]

0.005 is the correct answer i hope this helps man :)

8 0

3 years ago