Answer:
Manganese decreases from 4+ to 2+ (reduced and oxidizing agent) and nitrogen increases from 2+ to 5+ (oxidized and reducing agent).
Explanation:
Hello there!
In this case, according to the given redox reaction, we rewrite it as a convenient first step:
Next, we assign the oxidation numbers as follows:
Thus, we can see that both manganese and nitrogen undergo a change in their oxidation number, the former decreases from 4+ to 2+ (reduced and oxidizing agent) and the latter increases from 2+ to 5+ (oxidized and reducing agent).
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- <em>NH</em> <em> </em><em>at </em><em>5</em><em> </em><em>atm</em>
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<h2><em>hope</em><em> it</em><em> helps</em><em>!</em></h2>
<em>correct</em><em> me</em><em> if</em><em> </em><em>I'm</em><em> </em><em>wrong</em>
I think there is 4 electrons in the outer shell of 14 atomic number. If I'm wrong, know that I'm not very good.
The combination of an atom with other atom is bonding. Or break apart from other substance is breaking of interaction.
The bonding or interaction (inter-atomic) are due orbitals and electrons present in these orbitals
The atom consists of
a) a central nucleus which has proton and neutrons: they do not take part in chemical reactions
b) the part other than nucleus which has shells, sub shells and orbitals
These orbitals have electrons.
So the outer part of nucleus takes part in any combination with other substance
