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maksim [4K]
4 years ago
10

What are electron configurations?

Chemistry
2 answers:
olasank [31]4 years ago
8 0

Answer:

In atomic physics and quantum chemistry , the electron configuration is the distribution of electrons of an atom or molecule (or other physical structure) in atomic or molecular orbitals. For example, the electron configuration of the neon atom is 1s 2 2s 2 2p 6, using the notation explained below.

Explanation:

i found it on google

lutik1710 [3]4 years ago
3 0

Answer:

To calculate an electron configuration, divide the periodic table into sections to represent the atomic orbitals, the regions where electrons are contained. Groups one and two are the s-block, three through 12 represent the d-block, 13 to 18 are the p-block and the two rows at the bottom are the f-block.

Explanation:

In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals. For example, the electron configuration of the neon atom is 1s² 2s² 2p⁶, using the notation explained below.

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The chemical formula for sodium citrate is Nag Cs H5O7
Yuliya22 [10]

Answer:

C. Sodium citrate is a compound with a total of 21 atoms

Explanation:

Here's to help reassure you that the answer is correct, look at the picture

3 0
3 years ago
In the addition of hbr to 1-butyne the electrophile in the first step of the mechanism is
irga5000 [103]
Answer:
            <span>In the addition of hbr to 1-butyne the electrophile in the first step of the mechanism is <u>Hydrogen atom of HBr</u>.

Explanation:
                   In this reaction first of all HBr approaches the triple bond. A Pi Complex (weak inter-molecular interactions) is formed between the two molecules. And the triple bond attacks the partial positive hydrogen atom creating a negative charge on Bromine along with positive charge on itself (Sigma Complex). In second step the negative Bromide attacks the positive carbon of Butyne.</span>
7 0
3 years ago
How many molecules in each sample?<br><br> 64.7 g N2<br> 83 g CCl4<br> 19 g C6H12O6
lilavasa [31]

Answer:

  • 1.39x10²⁴ molecules N₂
  • .25x10²³ molecules CCl₄
  • 6.38x10²² molecules C₆H₁₂O₆

Explanation:

First we <u>convert the given masses into moles</u>, using the <em>compounds' respective molar mass</em>:

  • 64.7 g N₂ ÷ 28 g/mol = 2.31 mol N₂
  • 83 g CCl₄ ÷ 153.82 g/mol = 0.540 mol CCl₄
  • 19 g C₆H₁₂O₆ ÷ 180 g/mol = 0.106 mol C₆H₁₂O₆

Then we multiply each amount by <em>Avogadro's number</em>, to <u>calculate the number of molecules</u>:

  • 2.31 mol N₂ * 6.023x10²³ molecules/mol = 1.39x10²⁴ molecules
  • 0.540 mol CCl₄ * 6.023x10²³ molecules/mol = 3.25x10²³ molecules
  • 0.106 mol C₆H₁₂O₆ * 6.023x10²³ molecules/mol = 6.38x10²² molecules
3 0
3 years ago
if 1.0 L of a 2.0 M solution contains 1.204 * 10^24 molecules of a solute, how many molecules of solute will 1.0 L of a 0.5 M so
Rama09 [41]

The formula for molariy is nomber of moles/volume

0.5=n/1=>n=0.5 moles

one mole contains 6.023*10^23 molecules

so 0.5 contain 3.0115*10^23 molecules

4 0
3 years ago
The decantate from Question 1 that possibly contains K, Zn, or Cr, is neutralized with acetic acid and divided into the appropri
stepladder [879]

Answer:

2 that is Calcium (Ca) and Manganese (Mn)

Explanation:

Add dithizone in chloroform and look for a red complex formation.

4 0
3 years ago
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