C it illustrates possible outcomes
Mass = 473.2 g
Explanation:
Given data:
Mass of cobalt(III) nitrate = 206 g
Mass of silver bromide produced = ?
Solution:
Chemical equation:
CoBr₃ + 3AgNO₃ → 3AgBr + Co(NO₃)₃
Number of moles of cobalt(III) nitrate:
Number of moles = mass/ molar mass
Number of moles = 206 g/ 245 g/mol
Number of moles = 0.84 mol
Now we will compare the moles of cobalt(III) nitrate with silver bromide.
Answer:
Chemical equation:
HNO₃ + Al(OH)₃ → Al(NO₃)₃ + H₂O
Explanation:
Chemical equation:
HNO₃ + Al(OH)₃ → Al(NO₃)₃ + H₂O
Balanced chemical equation:
3HNO₃ + Al(OH)₃ → Al(NO₃)₃ + 3H₂O
Ionic equation:
3H⁺ + 3NO⁻₃(aq) + Al(OH)₃(s) → Al³⁺(aq) + 3NO₃⁻¹(aq) + 3H₂O(l)
Net ionic equation:
Al(OH)₃(s) + 3H⁺(aq) → Al³⁺(aq) + 3H₂O(l)
The NO⁻₃ are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.
Spectator ions:
These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.
