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Serhud [2]
3 years ago
14

What does the big bang theory suggest

Physics
1 answer:
Alika [10]3 years ago
7 0

Answer:

The Big Bang Theory is the leading explanation about how the universe began. At its simplest, it says the universe as we know it started with a small singularity, then inflated over the next 13.8 billion years to the cosmos that we know today.

Explanation: Hope this help! :)

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Mass of the are is 2100 kg
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Explain why the direction of the south equatorial current changes
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Some scientist believe that the ozone layers of the earth had been weakening and the waters or current changes direct ever 5-7 month.
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If a body of mass 5og moves in a circular path of radius 10cm .find work done
Sindrei [870]

Answer:

0Nm, no work is done.

Explanation:

Work done is defined as the Force per distance meaning force times the distance moved in the direction of the force.

Now the body of mass 50g has a centripetal force acting on it directed towards the centre. Now in actuality the body stays along the circle it doesn't really move to the centre of the circle.

Hence the force doesn't move a distance, and so from the definition of work done;

F×d ; d =0

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3 0
3 years ago
Assume a beam of light hits the boundary separating medium 1, with index of refraction n1 and medium 2, with index of refraction
Reptile [31]

Answer:

option C

Explanation:

Given,

Refractive index of medium 1 = n₁

Refractive index of medium 2 = n₂

For total internal reflection to take place light should move from denser medium to the rarer medium.

Here Total internal reflection take place at the boundary of medium 1 and medium 2 so, the refractive index of medium 1 is more than medium 2

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3 0
3 years ago
A loop of wire is carrying current of 2 A . The radius of the loop is 0.4 m. What is the magnetic field at a distance 0.09 m alo
HACTEHA [7]

Answer:

B=2.91\ \mu T

Explanation:

Given that,

The current in the loop, I = 2 A

The radius of the loop, r = 0.4 m

We need to find the magnetic field at a distance 0.09 m along the axis and above the center of the loop. The formula for the magnetic field at some distance is given as follows :

B=\dfrac{\mu_o}{4\pi }\dfrac{2\pi r^2 I}{(r^2+d^2)^{3/2}}

Put all the values,

B=10^{-7}\times \dfrac{2\pi \times 0.4^2 \times 2}{(0.4^2+0.09^2)^{3/2}}\\\\=2.91\times 10^{-6}\ T\\\\or\\\\B=2.91\ \mu T

So, the required magnetic field is equal to 2.91\ \mu T.

3 0
3 years ago
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