Some are out but will be on Netflix June 17
The downward pull of an object due to gravity is the object’s weight.
Answer:
a = 2 m/s2
Explanation:
we know from newtons 2nd law
F = ma.
we also know that from hookes law we have
F = kx
equate both value of force to get value of acceleration
kx = ma,
where,
k is spring constant = 8.0 N/m
x is maximum displacement 0.10 m
m is mass of object 0.40 kg
a = \frac{kx}{m}
= \frac{8 *0 .10}{0.40}
a = 2 m/s2
Answer:
√(6ax)
Explanation:
Hi!
The question states that during a time t the motorcyle underwent a displacement x at constant acceleration a starting from rest, mathematically we can express it as:
x=(1/2)at^2
Then the we need to find the time t' for which the displacement is 3x
3x=(1/2)a(t')^2
Solving for t':
t'=√(6x/a)
Now, the velocity of the motorcycle as a function of time is:
v(t)=a*t
Evaluating at t=t'
v(t')=a*√(6x/a)=√(6*x*a)
Which is the final velocity
Have a nice day!
Answer:
Explanation:
I think this answer would be 1m to the left.
