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Deffense [45]
3 years ago
7

Give you point but please i need help in physcis

Physics
1 answer:
Anastasy [175]3 years ago
7 0

Explanation:

Hi

Hi

Hi

Hi

BRAINILIEST PLEASE

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Convert 66.2 mi/h to m/s. 1 mi = 1609 m.<br> Answer in units of m/s.
Kryger [21]

Answer:

Explanation:

66.2mi/h to m/s

\frac{1609m}{1mi}×\frac{66.2mi}{1h}×\frac{1h}{60min}×\frac{1min}{60s}

  1. mi will go with mi
  2. h with h
  3. min with min
  4. m/s is left

\frac{1609*66.2}{60*60}= 29.58772222

Pls make sure of the way of solving to be sure...

4 0
4 years ago
Car's mass is 950kg. It's driven at 100km/h. How big is the kinetic energy?
polet [3.4K]

Answer:

4750000 J

Explanation:

Kinetic Energy= 1/2* mass* velocity²

1/2*950*100²=4750000

8 0
3 years ago
Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 4.50 m above
Virty [35]

8.98×10^6\:\text{m}

Explanation:

First we need to find the acceleration due to gravity on the planet. The wrench took 0.809 s to fall from a height of 4.50 m so we can use the equation

y = -\frac{1}{2}gt^2

Solving for g, we get

g = -\dfrac{2y}{t^2} = -\dfrac{2(-4.50\:\text{m})}{(0.809\:\text{s})} = 13.8\:\text{m/s}^2

Recall that the acceleration due to gravity on a planet's surface can be written as

g = G\dfrac{M_p}{R_p^2}

We can express the mass of the planet M_p in terms of its density \rho as follows:

M_p = \rho \left(\dfrac{4\pi}{3}R_p^3\right) = \dfrac{4\pi}{3}\rho R_p^3

The expression for g then becomes

g = \dfrac{G}{R_p^2} \left(\dfrac{4\pi}{3}\rho R_p^3\right) = \dfrac{4\pi G}{3}\rho R_p

Solving for R_p, we get

R_p = \dfrac{3g}{4\pi G\rho}

\:\:\:\:\:\:\:= \left[\dfrac{3(13.8\:\text{m/s}^2)}{4\pi (6.674×10^{-11}\:\text{Nm}^2\text{/kg}^2)(5500\:\text{kg/m}^3)}\right]

\:\:\:\:\:\:\:= 8.98×10^6\:\text{m}

3 0
3 years ago
As sound waves move from air to glass, the wave property of ________ will cause the wave to bend in that direction
Zarrin [17]
<span>The amplitude because that controls the height of the wave. Correct answer: Amplitude.</span>
5 0
4 years ago
A student decides they would like to have hands-on experience when it comes to transformers. The student takes an iron core (squ
Sergeu [11.5K]

Answer:

a ) 3 v

b ) 400 mA

Explanation:

In case of transformer there is relation between no of turns in primary and secondary coils and voltage input and output as follows

V₁ / V₂ = n₁ / n₂

Where V₁ and V₂ are input and output voltage and n₁ and n₂ are no of turns of primary and secondary coils.

Here V₁ = 1.5 v , V₂ = ? , n₁ = 10 , n₂ = 20

Put the values in the equation above

1.5 / V₂ = 10 / 20

V₂ = 3 v.

Similarly formula for current is as follows

I₁ / I₂ = n₂ / n₁

Whereas I₁ and I₂ are current in primary and secondary coil

Put the values in the equation above

I₁ / 200 mA = 20 / 10

I₁ = 400 mA.

6 0
3 years ago
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