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diamong [38]
3 years ago
6

Ikes teacher tells him that this process has caused each strip of tape to gain a negative electric charge. What could ike do nex

t to demostrate that the negative charge of each strip has generated an electric field
Physics
1 answer:
bija089 [108]3 years ago
3 0

Answer:

Explanation:

Ike will need to bring positively charged object near one end of the tape, electrons in the tape act like a conductor and will be attracted to the end near the positively charged object. This leaves the other end of the tape positively charged as a result of induction. Therefore, when Ike touch the positive end of the metal rod, electrons from his body will be attracted to the positive rod and transfer onto the rod. When he remove his finger, the rod has more electrons and is will be negatively.

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Answer:

q=10^{-6}(e^{-4000t}-4e^{-1000t}+3)C

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E(t)=\sum{Voltage \ Drop}\\\\L\frac{d^2q}{dt^2}+R\frac{dq}{dt}+\frac{1}{C}q=E(t)\\\\\\\frac{d^2q}{dt^2}+5000\frac{dq}{dt}+\frac{1}{0.25\times10^{-6}}q=12\\\\\frac{d^2q}{dt^2}+5000\frac{dq}{dt}+4000000q=12\\\\m^2+5000m+4000000=0\\\\(m+4000)(m+1000)=0\\\\m=-4000  \ or \ m=-1000\\\\q_c=c_1e^{-4000t}+c_2e^{-1000t}

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Q(t)=A,\ Q\prime(t)=0,Q\prime \prime(t)=0\\\\0+0+4000000A=12\\\\A=3\times10^{-6}\\\\Q(t)=3\times10^{-6},\\\\q=q_c+Q(t)\\\\q=c_1e^{-4000t}+c_2e^{-1000t}+3\times10^{-6}\\\\q\prime=-4000c_1e^{-4000t}-1000c_2e^{-1000t}\\q\prime(0)=0\\\\-4000c_1-1000c_2=0\\c_1+c_2+3\times10^{-6}=0\\\\#solving \ simultaneously\\\\c_1=10^{-6},c_2=-4\times10^{-6}\\\\q=10^{-6}e^{-4000t}-4\times10^{-6}e^{-1000t}+3\times10^{-6}\\\\q=10^{-6}(e^{-4000t}-4e^{-1000t}+3)C

Hence the charge at any time, t is q=10^{-6}(e^{-4000t}-4e^{-1000t}+3)C

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