Answer:
72 m/s
Explanation:
D1 = 3 cm, v1 = 2 m/s
D2 = 0.5 cm,
Let the velocity at narrow end be v2.
By use of equation of continuity
A1 v1 = A2 v2
3.14 × 3 × 3 × 2 = 3.14 × 0.5 ×0.5 × v2
v2 = 72 m/s
Answer:
1963.93 Moles
Explanation:
-We know the standard conversion ratio for the volume of a mole is 
Given volume of rooms as 
Convert the volume into liters:
#From our conversion ratio above, we get the volume of air molecules in moles as:
Hence, the volume of air molecules is 1963.93 Moles
Answer:
The girl will move with constant velocity
Explanation:
If after a certain time t_0 the velocity of the girl is v_0 =gt_0 and the upward force on the girl due to rope is mg ,where g is gravitational acceleration. Then the girl will move down with the constant velocity v_0 .
The girl will move with constant velocity,as explained above.
Answer:
2.41 L
Explanation:
We can solve the problem by using the ideal gas equation, which can be rewritten as:
where we have:
(initial pressure is stp pressure)
is the initial volume
is the initial temperature (stp temperature)
is the final pressure
is the final volume
is the final temperature
By substituting the numbers inside the formula and solving for V2, we find the final volume:
which corresponds to 2.41 L.
Answer:
Current = dQ/dt
or I = dQ/dt
Where I represents current.
Which is the rate of flow of charge.
Q=4 + 2t + t²
dQ/dt = 2 + 2t --- This is the relation that gives the instantaneous current.
At time t=2sec
dQ/dt = I = 2 + 2t
= 2 + 2(2)
=2 + 4
= 6A.
