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Yuliya22 [10]
3 years ago
8

A​ town’s January high temperatures average 36 degrees​ (F) with a standard deviation of 10 degrees while in July the mean high

temperature is 74 degrees and the standard deviation is 8. In which month is it more unusual to have a day with a high temperature of​ 55? explain
Mathematics
1 answer:
n200080 [17]3 years ago
3 0

Answer:

55 degrees is more unusual in July as it is away from mean temperature as compared to January.

Step-by-step explanation:

We are given the following information in the question:

January:

Mean, μ = 36 degrees

Standard Deviation, σ = 10 degrees

July:

Mean, μ = 74 degrees

Standard Deviation, σ = 8 degrees

We calculate z scores corresponding to x = 55.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

January:

z_{score} = \displaystyle\frac{55-36}{10} = 1.9

July:

z_{score} = \displaystyle\frac{55-74}{8} = -2.375

Thus, 55 degrees is more unusual in July as it is away from mean temperature as compared to January.

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In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0
2 years ago
If the Ferris Wheel goes around twice in 1 1/2 minutes, how many times will it go around in nine minutes
Tanzania [10]

Answer:

12

Step-by-step explanation:

I am pretty sure this is the answer. If it is correct i can give the explanation

4 0
3 years ago
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Kryger [21]

From the information given,

x represents number of small boxes while y represents number of large boxes.

If each small box can hold 6 books and each large box can hold 10 books, it means that the expression for the number of books that x small boxes and y large boxes can hold is

6x + 10y

If James can pack up to 110 books, it means that the number of books that he can pack is less than or equal to 110. The inequality representing this scenario is

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Dividing both sides of the equation by 10, we have

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The graph is shown below

The inequality that represents this sitaution is 6x + 10y ≤ 110

The graph of the inequality wil have solid boundary at y = - 3x/5 + 11

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3 0
1 year ago
Sole by substitution <br> y= -7x + 6<br> y = -10.
igomit [66]
7-63.92.28 is the answer hopes this helps
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2 years ago
What integer <br> Describes a profit of <br> $650? Please show your work.
inna [77]
+$650 because there is no loss of money
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