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Leona [35]
3 years ago
7

PLEASE HELP ITS DUE BY MIDNIGHT I HAVE LIKE 30 MINS!!! The linear regression for this print-out relates the amount of oxygen in

your spaceship measured in liters as a function of time In hours
Interpret the meaning of the slope in the context of the problem

Mathematics
1 answer:
dezoksy [38]3 years ago
7 0

Answer:

Please check explanations

Step-by-step explanation:

Here, we want to interpret the meaning of the slope

The slope generally refers to the change in y values with corresponding change in x value

with respect to this question, we can see that the slope is negative

What this mean is that the rate of change in the level of oxygen measured in liters is decreasing with an increase in the time

This means that as more time elapses, more oxygen is used up leading to a decrease in the liters of oxygen present

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A random sample of 225 individuals working in a large city indicated that 45 are dissatisfied with their working conditions. Bas
Lorico [155]

Answer:

CI 90 %  =  [  0,165  ;  0,235 ]

Lower limit     0,165

upper limit      0,235

Step-by-step explanation:

Sample information:

sample size    n  =  225

number of dissatisfied  individuals   x  =  45

p = 45/225

p = 0,2    and  q =  1 -  p   q  =  1  -  0,2   q  =  0,8

p*n = 0,2*225   =  45    and   q*n   =  0,8*225  =  180

p*n  and q*n  big enough to use the approximation of binomial distribution to normal distribution

90 % of Confidence Interval   then a significance level is  α  = 10%

α  =  0,1 in z table we get z(c) for that significance level

z(c) = 1,28

CI 90 %   =  [  p  ±  z(c)*√(p*q)/n ]

z(c) * √(p*q)/n    =  1,28 *  √ ( 0,2*0,8)/225

z(c) * √(p*q)/n    =  1,28 * 0,027

z(c) * √(p*q)/n    =  0,035

CI 90 %  =  [  0,2  ±  0,035 ]

CI 90 %  =  [  0,165  ;  0,235 ]

Lower limit     0,165

upper limit      0,235

3 0
3 years ago
In a test of the hypothesis
Marizza181 [45]

Answer:

Step-by-step explanation:

Given that

sample size =n= 50

x bar = sample mean = 10.8

s = sample std deviation = 3.3

Mean difference = 50-10 = 40

Std error of sample = std dev / sqrt n=\frac{3.3}{\sqrt{40} } =0.5218

Since population std dev is not known, we have to use t test

Test statistic t = Mean diff/std error = \frac{40}{0.5218} =76.66

df = 39

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Since p < 0.09 our significance level, we reject our null hypothesis.

A. There is sufficient evidence to reject Upper H 0 for alpha greater than 0.09

4 0
3 years ago
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