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yulyashka [42]
3 years ago
5

Dave is 8 years younger than 4 times Julia‘s age. If Dave is 16, how old is Julia?

Mathematics
1 answer:
Yanka [14]3 years ago
6 0

Julia is 6 years old. (A)

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What is this?<br> It is a alternate question
Eduardwww [97]

Answer:

complimentary angles

Step-by-step explanation:

6 0
3 years ago
Rita paid $82 for 5 trees and 1 shrub. Lilly bought 2 trees and 1 shrub for $37. Find the cost per tree and the cost per shrub.
N76 [4]

Answer:

trees cost $15

Shrub cost $7

Step-by-step explanation:

Given data

Rita paid $82 for 5 trees and 1 shrub

5x+y= 82---------1

Lilly bought 2 trees and 1 shrub for $37

2x+y= 37----------2

from 1

y= 82-5x

put the value of y in 2

2x+82-5x= 37

2x-5x= 37-82

-3x=-45

x= 45/3

x=$15

put the value of x in 1

5(x)+y= 82

5*15+y=82

75+y=82

y=82-75

y=$7

Hence, trees cost $15

Shrub cost $7

4 0
3 years ago
Find the difference <br><br><br>-2(c + 2.5) - 5(1.2c + 4)​
Vikentia [17]
Answer:
|−∣=7
Explanation:

∣−∣
= |(-2-5)|
= |-2-5|
= | -7|=7
8 0
2 years ago
A population of bacteria begins with 1500 bacteria and grows to 4500 in one hour.
dezoksy [38]

The function that represents the growth of this culture of bacteria as a function of time is; P = 1500e^(1.0986t)

<h3>How to calculate Exponential Growth?</h3>

The formula for exponential growth is;

P = P₀e^(rt)

where;

P = current population at time t

P₀ = starting population

r = rate of exponential growth/decay

t = time after start

Thus, from our question we have;

4500 = 1500 * e^(r * 1)

4500/1500 = e^r

e^r = 3

In 3 = r

r = 1.0986

Thus, the function that represents the growth of this culture of bacteria as a function of time is;

P = 1500e^(1.0986t)

For the culture to double, then;

P/P₀ = 2. Thus;

e^(1.0986t) = 2

In 2 = 1.0986t

t = 0.6931/1.0986

t = 0.631 hours

Read more about Exponential Growth at; brainly.com/question/27161222

#SPJ1

4 0
2 years ago
21 plus 4x equal 61 what equal 61
kvasek [131]

Answer:

x = 10

Step-by-step explanation:

61 - 21 = 40
40 / 4 = 10
x = 10

6 0
3 years ago
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