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SCORPION-xisa [38]
3 years ago
5

Gravity is a force between any two objects with mass wht doesn’t a person feel a gravitational force between them herself and an

other person
Physics
1 answer:
kipiarov [429]3 years ago
6 0
It is because both of them are attracted towards earth where the heavier body gravity field influence is more in comparision to small. For eg; there are two magnet with less power in besides of huge power or magnetic influence then both of the less power magnet are attracted towards the huge one rather than attracting themselves.


Hope its helps u!
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Calculating the Mass of a Granite Monument
Volgvan

Answer:

m = 684,865,8 g

Step-by-step explanation

V = 25,365.4 cm^3            Is volume

r = 27g/cm^3                     Is density

To calculate mass you use formula:

m= V*r

m = 25,365.4 x 27

m = 684,865,8 g

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3 years ago
A motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travel
Misha Larkins [42]

Explanation:

Consider the kinematic equation,

x  = vt +  \frac{1}{2} a {t}^{2}

where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,

x = 3(1.8) +  \frac{1}{2} (9.3) {1.8}^{2}

through simple algebra we get

x = 20.466

where this is the distance traveled in meters.

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3 years ago
A slingshot can project a pebble at a speed as high as 38.0 m/s. (a) If air resistance can be ignored, how high (in m) would a p
kipiarov [429]

Answer:

73.67 m

Explanation:

If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:

y(t) = y_0 + V_0 * t + \frac{1}{2} a t^2

V(t) = V_0 + a * t,

Where y_0 its our initial height, V_0  our initial speed, a the acceleration and t the time that has passed.

For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.

We can plug this values in our equations, to obtain:

y(t) =  38 \frac{m}{s} * t - \frac{1}{2} g t^2

V(t) = 38 \frac{m}{s} - g * t

note that the acceleration point downwards, hence the minus sign.

Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:

0 m = 38 \frac{m}{s} - g * t

and obtain:

t = 38 \frac{m}{s} / g

t = 38 \frac{m}{s} / 9.8 \frac{m}{s^2}

t = 3.9 s

Plugin this time on our first equation we find:

y = 38 \frac{m}{s} * 3.9 s - \frac{1}{2} 9.8 \frac{m}{s^2} (3.9 s)^2

y=73.67 m

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3 years ago
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Answer:

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