Question

A motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travels in this time​

Answer 1

Explanation:

Consider the kinematic equation,

$x = vt + \frac{1}{2} a {t}^{2}$

where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,

$x = 3(1.8) + \frac{1}{2} (9.3) {1.8}^{2}$

through simple algebra we get

$x = 20.466$

where this is the distance traveled in meters.