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masha68 [24]
3 years ago
8

A motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travel

s in this time​
Physics
1 answer:
Misha Larkins [42]3 years ago
4 0

Explanation:

Consider the kinematic equation,

x  = vt +  \frac{1}{2} a {t}^{2}

where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,

x = 3(1.8) +  \frac{1}{2} (9.3) {1.8}^{2}

through simple algebra we get

x = 20.466

where this is the distance traveled in meters.

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