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Vedmedyk [2.9K]
2 years ago
10

Find the unbalanced force acting on the object.

Physics
1 answer:
gtnhenbr [62]2 years ago
7 0

To find the unbalanced force you have to use the formula *net force=resultant force=unbalanced force =outside force).

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What are the standard units of length, mass, and volume in the<br> metric system?
antoniya [11.8K]

Answer:

Meter, Gram and Liter.

Explanation:

In the metric system, the standard units for the below are;

Length  - Meter

Mass     - Gram

Volume - Liter.

8 0
3 years ago
What do you mean by velocity ratio of a wheel and axle​
IgorC [24]

Answer:

Explanation:

In wheel and axle. …with the system is the velocity ratio, or the ratio of the velocity (VF) with which the operator pulls the rope at F to the velocity at which the weight W is raised (VW). This ratio is equal to twice the radius of the large drum divided by the difference…

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3 years ago
A boy starts from point A and moves 5 units toward the east, then turns back and moves 3 units toward the west. What is the disp
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The displacement of the boy is 2 units
4 0
3 years ago
A baseball pitcher throws the ball towards the batter at 90 mph. His bat connects with the ball for a line drive, after which th
forsale [732]

Answer:

F=-18412.9N, where the minus indicates the direction is opposite to that of the throw.

Explanation:

a)

Since MKS stands for meter-kilogram-second and we know that:

1\ hour = 3600\ seconds

1\ mile = 1600\ meters

1000g = 1kg

We can write that:

\frac{1\ hour}{3600\ seconds}=1

\frac{1600\ meters}{1\ mile}=1

\frac{1kg}{1000g}=1

These are conversion factors, equal to 1, so multiplying our results by them won't change their value, only their units.

So we have that:

90 mph=90 \frac{miles}{hour}(\frac{1\ hour}{3600\ seconds})(\frac{1600\ meters}{1\ mile})=40m/s

110 mph=110 \frac{miles}{hour}(\frac{1\ hour}{3600\ seconds})(\frac{1600\ meters}{1\ mile})=48.89m/s

145 g=145 g(\frac{1kg}{1000g})=0.145kg

b)

Newton's 2nd Law tells us that F=ma, and the definition of acceleration is a=\frac{\Delta v}{\Delta t}, so we have:

F=m\frac{\Delta v}{\Delta t}=m\frac{v_f-v_i}{t}

Taking the throw direction as the positive one, for our values we have:

F=m\frac{v_f-v_i}{t}=(0.145kg)\frac{(-48.89m/s)-(+40m/s)}{0.0007s}=-18412.9N

4 0
3 years ago
In an internal combustion engine, heat flow into a gas causes it to <br> .
Sunny_sXe [5.5K]

Answer:

Along path BC of the Otto cycle, heat transfer Qh into the gas occurs at constant volume, causing a further increase in pressure and temperature. This process corresponds to burning fuel in an internal combustion engine, and takes place so rapidly that the volume is nearly constant.

7 0
1 year ago
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