Answer:
m = -4
Step-by-step explanation:
- 36 - m = 8(4+2m)
- 36 - m = 32+16m (to remove m from the left side, we need to add m to both sides)
- 36 = 32+17m (subtract 32 from both sides)
- 68 = 17m (divide by 17 on both sides)
-4 = m
The answer would be 198/300. That simplified would be 33/50. If you want a percent, it would be 66%.
Answer:
a) the probability that the minimum of the three is between 75 and 90 is 0.00072
b) the probability that the second smallest of the three is between 75 and 90 is 0.396
Step-by-step explanation:
Given that;
fx(x) = { 1/5 ; 50 < x < 100
0, otherwise}
Fx(x) = { x-50 / 50 ; 50 < x < 100
1 ; x > 100
a)
n = 3
F(1) (x) = nf(x) ( 1-F(x)^n-1
= 3 × 1/50 ( 1 - ((x-50)/50)²
= 3/50 (( 100 - x)/50)²
=3/50³ ( 100 - x)²
Therefore P ( 75 < (x) < 90) = ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx
= 3/50³ [ -2 (100 - x ]₇₅⁹⁰
= (3 ( -20 + 50)) / 50₃
= 9 / 12500 = 0.00072
b)
f(k) (x) = nf(x) ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k
Now for n = 3, k = 2
f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))
= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)
= 6/50³ ( 150x - x² - 5000 )
therefore
P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx
= 99 / 250 = 0.396
Well, you take 0.199 find the hundredths place, which is the 9 to the left in this example, and decide whether the number to the right of the nine is more than 5, which it is, so we round the 9 up. However, we can't just make it 10 hundredths, so we have to simplify it to 1 tenth and add it onto the tenths place to make 0.20.
