Answer : The crystal structure of Niobium is, BCC (Z=2)
Explanation :
Nearest neighbor distance, r =
Atomic mass of niobium (Nb) = 92.91 g/mole
Avogadro's number
First we have to calculate the cubing of edge length of unit cell for BCC and FCC crystal lattice.
For BCC lattice :
For FCC lattice :
Now we have to calculate the density of unit cell for BCC and FCC crystal lattice.
Formula used :
.............(1)
where,
= density
Z = number of atom in unit cell (for BCC = 2, for FCC = 4)
M = atomic mass
= Avogadro's number
a = edge length of unit cell
Now put all the values in above formula (1), we get
From this information we conclude that, the given density is approximately equal to the density of BCC unit lattice.
Therefore, the crystal structure of Niobium is, BCC (Z=2)
Answer:
There 11,238,513 different Powerball
Answer:
False
Explanation:
Bella counts products in finished goods inventory and she counts kits in various stages of manufacturing.
Answer: I will ask my dad he knows
Explanation:
Answer:
Explanation:
Given Parameters
Mass of slender, m = 15kg
Length of AB, a = 4.5m
Initial velocity of slender, = 0m/s
we draw the initial condition of slender as shown in the attached file 1
Now consider the instantaneous center at C
Write the expression to calculate the kinetic energy at initial position ()
substitute the values in the above expression
Write the expression to calculate the Potential energy at initial position ()
here, is the position of the center of mass in initial position
Substitute the values in the above expression
= 331.088Nm
the condition of the slender at the final position is as shown in the second file attached
check other files for extra details