R=0.5772 (im trying to post it says wrong answer so not sure)
Answer:
How about asking your math teacher for help, instead of going to the internet? As your math teacher, I think it would be a better idea than having your teacher find your internet post!
Step-by-step explanation:
I'll be waiting for an email.
Answer:
Solution:
Given : In triangle ABC right angled at B.
To Prove :
Construction: Draw B D perpendicular AC.
Proof: 1. Triangle ABC is similar to triangle BDC 1. Angle ABC = Angle BDC and Angle BCA = Angle BCD
2. = AC × DC 2. BC ÷ DC = AC ÷ BC because triangle ABC is similar to triangle BDC
3. Triangle ABC is similar to triangle ABD 3. Angle ABC = Angle BAD and Angle BAC = Angle ABD
4. = AC × AD 4. AB ÷ AD = AC ÷ AB because triangle ABC is similar to triangle ABD
5.
= AC (AD + DC)
6. Adding Statement 1 and Statement 2
7.
→→→Statement 3 is incorrect.It should be replaced by, Angle ABC = Angle ADB and Angle B AC = Angle BAD .
hope i could help also if u have time please mark me as brainlest
Answer:
48.8°
Step-by-step explanation:
We solve using sine rule
The formula is given as
p/sin P = r/sin R
In APQR, P = 83°, p = 285 m, r = 216 m.
Calculate R.
Hence, solving for R
285/sin 83 = 216/sin R
Cross Multiply
285 × sin R = sin 83 × 216
sin R = sin 83 × 216/285
R = arc sin (sin 83 × 216/285)
R = 48.78527°
Approximately = 48.8°
Therefore, R = 48.8°
