The base case is the claim that
which reduces to
which is true.
Assume that the inequality holds for <em>n</em> = <em>k </em>; that
We want to show if this is true, then the equality also holds for <em>n</em> = <em>k</em> + 1 ; that
By the induction hypothesis,
Now compare this to the upper bound we seek:
because
in turn because
The square root of 16=4, 4x2=8, x2=8.
Answer:
SEE BELOW
Step-by-step explanation:
1. find value of m
a^2 + b^2 = c^2
7.5^2+10^2=c^2
15+100=c^2
115=c^2
square it
=10.7 (not answer)
a^2+b^2=c^2
10.7^2+30^2=c^2
114.49+900=c^2
1014.49=c^2
square it
m=31.9
2.20^2 + 21^2 = 841
29^2=841
yes the triangle is right angled !!!
hope this helps :)
It's 8 because the number in front of the variable is the slope, while the past 30 is the y intercept
Answer:
32 units squared
Step-by-step explanation:
This is kind of a weird shape, so split it into smaller shapes, in this case two triangles and a rectangle.
Both of the triangles have a base of 8 and a height of 2. Multiply the base and the height together, then divide by 2. 8*2/2 equals 8, so the area of each triangle is 8.
For the rectangle, the length is 2, and the width is 8. Multiply the length and the width together to get 16.
Finally, add the areas of all those smaller shapes together to get the area of the whole shape, 32 units squared.
