Answer:
Percentage yield = 25%
Explanation:
Given data:
Moles of C₈H₁₈ = 4 mol
Moles of O₂ = 4 mol
Actual yield of CO₂ = 28.16 g
Percentage yield = ?
Solution:
Chemical equation:
2C₈H₁₈ + 25 O₂ → 16CO₂ + 18H₂O
Now we will compare the moles of CO₂ with O₂ and C₈H₁₈.
C₈H₁₈ : CO₂
2 : 16
4 : 16/2×4=32 mol
O₂ : CO₂
25 : 16
4 : 16/25×4=2.56 mol
Mass of CO₂:
Mass = number of moles× molar mass
Mass = 2.56 mol ×44 g/mol
Mass = 112.64 g
Percentage yield:
Percentage yield = Actual yield /theoretical yield × 100
Percentage yield = 28.16 g / 112.64 g× 100
Percentage yield = 0.25× 100
Percentage yield = 25%
Answer: 70 metals,17 nonmetals,metalloids 6
Explanation:
Answer:
0.14 moles of Fe₂O₃
Explanation:
Given parameters:
Number of moles of Fe = 0.27moles
Unknown:
Number of moles of Fe₂O₃ = ?
Solution:
To solve this problem, we are going to the work from the known specie to the unknown using their number of moles.
We first obtain the balanced equation of the reaction;
4Fe + 3O₂ → 2Fe₂O₃
The equation above is balanced;
4 moles of Fe produced 2 moles of Fe₂O₃
0.27 moles of Fe will produce 
= 0.14 moles of Fe₂O₃
A periodic table is tabular arrangement of the chemical elements, ordered by their atomic number,electronic configuration and recurring chemical properties. carbon is in group 14 and period two. The atomic mass of carbon from periodic table is 12.01 g/mole
Answer:
(40 g O) / (15.99943 g O/mol) x (1 mol CaCO3 / 3 mol O) x (100.0875 g CaCO3/mol) =
83 g CaCO3
So answer D), although three significant digits are not justified.
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