Answer:
1000 gram
Explanation:
because mass is constant everywhere
Answer:
Volcanologists use many different kinds of tools including instruments that detect and record earthquakes (seismometers and seimographs), instruments that measure ground deformation (EDM, Leveling, GPS, tilt), instruments that detect and measure volcanic gases (COSPEC), instruments that determine how much lava is moving underground (VLF, EM-31), video and still cameras, infrared cameras, satellite imagers, webcams, etc!
Explanation:
I HOPE IT HELPED
K5O2
convert grams to moles, divide both by the smallest mole mass, multiply that until hole.
30.5 g K ÷ 39.10 = .78 mol
6.24 g O ÷ 16 = .39 mol
.78 mol ÷ .39 mol = 2.5
.39 mol ÷ .39 mol = 1
2.5 x 2 = 5
1 x 2 = 2
K5O2
Answer:
The majority of the molecules move from higher to lower concentration, although there will be some that move from low to high. The overall (or net) movement is thus from high to low concentration.
hope this helps!<3
Answer:
![\boxed {\boxed {\sf 0.80 \ mol\ F}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%200.80%20%5C%20mol%5C%20F%7D%7D)
Explanation:
We are asked to find how many moles are in 4.8 × 10²³ fluorine atoms. We convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of fluorine.
We will convert using dimensional analysis and set up a ratio using Avogadro's Number.
![\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}](https://tex.z-dn.net/?f=%5Cfrac%20%7B6.022%20%5Ctimes%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20F%7D%7B%201%20%5C%20mol%20%5C%20F%7D)
We are converting 4.8 × 10²³ fluorine atoms to moles, so we multiply the ratio by this number.
![4.8 \times 10^{23} \ atoms \ F *\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}](https://tex.z-dn.net/?f=4.8%20%5Ctimes%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20F%20%2A%5Cfrac%20%7B6.022%20%5Ctimes%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20F%7D%7B%201%20%5C%20mol%20%5C%20F%7D)
Flip the ratio so the units of atoms of fluorine cancel each other out.
![4.8 \times 10^{23} \ atoms \ F *\frac { 1 \ mol \ F}{6.022 \times 10^{23} \ atoms \ F}](https://tex.z-dn.net/?f=4.8%20%5Ctimes%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20F%20%2A%5Cfrac%20%7B%201%20%5C%20mol%20%5C%20F%7D%7B6.022%20%5Ctimes%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20F%7D)
![4.8 \times 10^{23} *\frac { 1 \ mol \ F}{6.022 \times 10^{23} }](https://tex.z-dn.net/?f=4.8%20%5Ctimes%2010%5E%7B23%7D%20%20%2A%5Cfrac%20%7B%201%20%5C%20mol%20%5C%20F%7D%7B6.022%20%5Ctimes%2010%5E%7B23%7D%20%7D)
Condense into 1 fraction.
![\frac { 4.8 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ F](https://tex.z-dn.net/?f=%5Cfrac%20%7B%204.8%20%5Ctimes%2010%5E%7B23%7D%20%7D%7B6.022%20%5Ctimes%2010%5E%7B23%7D%20%7D%20%5C%20mol%20%5C%20F)
Divide.
![0.7970773829 \ mol \ F](https://tex.z-dn.net/?f=0.7970773829%20%5C%20mol%20%5C%20F)
The original measurement of atoms has 2 significant figures, so our answer must have the same. For the number we found, that is the hundredths place. The 7 in the thousandths tells us to round the 9 in the hundredths place up to a 0. Then, we also have to round the 7 in the tenths place up to an 8.
![0.80 \ mol \ F](https://tex.z-dn.net/?f=0.80%20%5C%20mol%20%5C%20F)
4.8 × 10²³ fluorine atoms are equal to <u>0.80 moles of fluorine.</u>