Question

Please help. I’m really struggling. No wrong answers please, if you don’t know it please don’t answer, I’m already failing the class.

Answer 1

Answer:

K₅Mn₅O₁₆

Explanation:

From the question given above, the following data were obtained:

Potassium (K) = 27.5 %

Manganese (Mn) = 37.5 %

Oxygen (O) = 35 %

Empirical formula =?

The empirical formula for the compound can be obtained as follow:

K = 27.5 %

Mn = 37.5 %

O = 35 %

Divide by their molar mass

K = 27.5 / 39 = 0.705

Mn = 37.5 / 55 = 0.682

O = 35 / 16 = 2.188

Divide by the smallest

K = 0.705 / 0.682 = 1

Mn = 0.682 / 0.682 = 1

O = 2.188 / 0.682 = 3.2 = 32/10 = 16/5

K = 1

Mn = 1

O = 16/5

Multiply by 5 to express in whole number

K = 1 × 5 = 5

Mn = 1 × 5 = 5

O = 16/5 × 5 =16

Thus, the empirical formula for the compound is K₅Mn₅O₁₆