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4 years ago

The product of sin 30° and sin 60° is same as the product blank of

Mathematics

2 answers:

hjlf4 years ago

5 0

Answer:

A. & A.

Step-by-step explanation:

sin(x) = cos(90-x)

sin(30) = cos(90-30) = 60

sin(60) = cos(90-60) = 30

Masja [62]4 years ago

5 0

Answer:

A. cos60° and A. cos30°

Step-by-step explanation:

We know that is A and B are complementary, so

sinA = cosB

sin30° = cos60° and

sin60° = cos30°

So,

sin30°·sin60° = cos60°·cos30°

The product of sin30° and sin60° is same as the product of cos60° and cos30°.

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Which answer choice below correctly identifies the 120th term in the sequence 9, 17, 25, 33 …?

nataly862011 [7]

Answer:

120th term = 961

where

a = first term

d = common difference

n = number of terms

Step-by-step explanation:

$a + (n - 1)d \\ 9 + (120 - 1)8 \\ 9 + (119)8 \\ 9 + 952 \\ 120th \: term = 961$

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3 years ago

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3 years ago

Convert 15/2 to a mixed fraction

stiks02 [169]

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3 years ago

If f(x) = 5x, what is y(x)?

Snezhnost [94]

Answer:

Step-by-step explanation:

y(x) and f(x) are similar in meaning; they both state that the dependent variable is a function of the independent variable x.

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8 0

3 years ago

A rectangle has the length of 22 inches less than 7 times the width. If the area of the rectangle is 3197 square inches, find th

Nikolay [14]

The length of rectangle is 139 inches

Solution:

Given that, area of the rectangle is 3197 square inches

Let "L" be the length of rectangle and "W" be the width of rectangle

Also given that rectangle has the length of 22 inches less than 7 times the width

Length = 7 times width - 22

L = 7W - 22

<em><u>The area of rectangle is given as:</u></em>

$\text {Area of rectangle }=\text { length } \times \text { width }$

Substituting the values we get,

$\begin{array}{l}{3197=(7 W-22)(W)} \\\\ {3197=7 W^{2}-22 W} \\\\ {7 W^{2}-22 W-3197=0}\end{array}$

On solving the above quadratic equation using quadratic formula,

$\text {For the quadratic equation } a x^{2}+b x+c=0 \text { where } a \neq 0$

$x=\frac{-b \pm \sqrt{\left(b^{2}-4 a c\right)}}{2 a}$

$\begin{array}{l}{\text {Here in } 7 \mathrm{W}^{2}-22 \mathrm{W}-3197=0} \\\\ {a=7 ; b=-22 ; c=-3197}\end{array}$

Substituting in above quadratic formula,

$\begin{array}{l}{W=\frac{-(-22) \pm \sqrt{\left((-22)^{2}-4(7)(-3197)\right)}}{2 \times 7}} \\\\ {W=\frac{22 \pm \sqrt{90000}}{14}=\frac{22 \pm 300}{14}} \\\\ {W=\frac{22+300}{14} \text { or } W=\frac{22-300}{14}} \\\\ {W=23 \text { or } W=-19.85}\end{array}$

Since width of rectangle cannot be negative, ignore negative value of "W"

So width W = 23 inches

Length L = 7W - 22 = 7(23) - 22 = 139 inches

Thus length of rectangle is 139 inches

8 0

4 years ago