All categories

2 years ago

NEED ANSWER REAL QUICK

Physics

2 answers:

vivado [14]2 years ago

4 0

Explanation:

when the circuit is broken or when a switch is open.

Sauron [17]2 years ago

3 0

Answer:c

A burned out bulb, dead battery, open switch, or discon- nected wire can open a circuit and stop the flow of current. conductor A material current can pass through easily. A good conductor has low resistance to the flow of electric charges. Metals, like aluminum, gold, and copper, are good conductors.

get what trying to tell u

Explanation:

You might be interested in

Which of the following are true for acceleration?

Fittoniya [83]

The SI unit for acceleration is m/s2 ( D)

6 0

2 years ago

The equation that relates two poles to the force between them and their separation is the ____ square law.

Ivenika [448]

A-exponential
You welcome

4 0

2 years ago

A circuit has a current of 1.2 A. If the voltage decreases to one third of its original amount while the resistance remains cons

Katen [24]

When resistance is constant, current is proportional to voltage. When 1/3 the voltage is applied, 1/3 the current will result.

(1/3)*(1.2 A) = 0.4 A

The resulting current will be 0.4 A.

8 0

2 years ago

A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find th

Rashid [163]

Answer:

The velocity of the particle = -1.92 m/s

The speed of the particle = 5.72 m/s

Explanation:

Given equation of motion;

$f(t) = 18 \ + \ \frac{48}{t} \ + \ 1$

Velocity is defined as the change in displacement with time.

$V = \frac{df(t)}{dt} = -\frac{48}{t^2} \\\\at \ t = 5 \ s\\\\V = -\frac{48}{5^2} = \frac{-48}{25} = - 1.92 \ m/s$

The distance traveled by the particle in 5 s:

$s = f(5) = 18 + \frac{48}{5} + 1\\\\s= 28.6 \ m$

The speed of the particle when t = 5s

$Speed = \frac{28.6}{5} = 5.72 \ m/s$

6 0

2 years ago

A 1.5-kg mass attached to an ideal massless spring with a spring constant of 20.0 N/m oscillates on a horizontal, frictionless t

Molodets [167]

Answer:

Explanation:

a ) angular frequency ω = $\sqrt{\frac{k}{m} }$

k is spring constant and m is mass attached

ω = $\sqrt{\frac{20}{1.5} }$

= 3.6515 rad / s

frequency of oscillation n = 3.6515 / (2 x 3.14)

= .5814 s⁻¹

x = .1 mcos(ωt)

= .1 mcos(3.6515t)

b ) maximum speed = ωA , A is amplitude

= 3.6515 x .1

= .36515 m /s

36.515 cm /s

maximum acceleration = ω²A

= 3.6515² x .1

= 1.333 m / s²

c ) Kinetic energy at displacement x

= 1/2 m ω²( A²-x²)

potential energy =1/2 m ω²x²

so 1/2 m ω²( A²-x²) = 1/2 m ω²x²

A²-x² = x²

2x² = A²

x = A / √2

6 0

3 years ago