Which is the metric standard for measuring energy?

What is the formula of the compound vanadium(V) oxide? Use the list of polyatomic ions and the periodic table to help you answer

Vaselesa [24]

Answer:

d

Explanation:

7 0

3 years ago

Read 2 more answers

What do scientist do to easily share measurement data they can understand

Jobisdone [24]

1. They use the same measuring system (metric)

2. Clearly and properly collect and record data, recording the procedure and results

3. Releasing the data into the public, letting everyone have access to it

maybe, I don't know what answer your teacher wants

3 0

3 years ago

Given the following reaction: 3D(g) + E(g) + 2F(g) → 5G(g) + 4H(g)

evablogger [386]

Answer:

Explanation:

Hello,

The law of mass action, allows us to know the required amounts, thus, for this chemical reaction it is:

$\frac{1}{-3} \frac{d[D]}{dt} =\frac{1}{-1} \frac{d[E]}{dt} =\frac{1}{-2} \frac{d[F]}{dt} =\frac{1}{5} \frac{d[G]}{dt} =\frac{1}{4} \frac{d[H]}{dt}$

Now, we answer:

(a)

$\frac{d[H]}{dt}=4*\frac{1}{-3} *(-0.12M/s)=0.16M/s$

(b)

$\frac{d[E]}{dt}=-1*\frac{1}{5} *(0.2M/s)=-0.04M/s$

(c) Since no initial data is specified, we could establish the rate of the reaction as based of the law of mass action:

$r=\frac{1}{-3} \frac{d[D]}{dt} =\frac{1}{-1} \frac{d[E]}{dt} =\frac{1}{-2} \frac{d[F]}{dt} =\frac{1}{5} \frac{d[G]}{dt} =\frac{1}{4} \frac{d[H]}{dt}$