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alex41 [277]
3 years ago
9

Okay I better get a good answer for this guy I'm puttin' all my money on it.

Physics
2 answers:
Black_prince [1.1K]3 years ago
3 0

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.

Explanation:

klio [65]3 years ago
3 0

Answer: Explanation:

Newton's third law of motion is simply whenever two objects interact,

they exert equal and opposite forces on each other.

This is often worded as 'every action has an equal and opposite reaction'. you have to remember two forces:  1 is act on two different objects , 2 are of the same type (i.e. both contact forces)

The statement simply means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs - equal and opposite action-reaction force pairs.

the attached is an example of "in every action, there is an equal and opposite and reaction.

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A square window with 80 meter sides is located on the vertical side of a large rectangular pool. The depth of the pool is 5 mete
ludmilkaskok [199]

Answer:

See explanation

Explanation:

Solution:-

- We will first set a datum as the free surface of water in the pool.

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- The depth of the pool is given to be 54 m. The top of the window is ( d = 43 m ) from the free surface.

- We are to determine the resultant hydro static force acting on the window.

- Hydro static force ( F ) acting on an object of area ( A ) fully immersed in fluid is given by the following relationship as follows:

                           F = Pc*A

Where,

                  Pc: The hydrostaic pressure acting on the centroid of the obect.

- The hydrostatic pressure acting on the centroid of the object immersed in any fluid can be expressed by the following defining relationship:

                           Pc = γ*yc

Where,

                          γ: The specific weight of the fluid

                          yc: The vertical distance from free-surface to the centroid.

- Assuming homogeneous distribution of material used for the window of square shape. The centroid coincides with the geometric center of the window which is as a distance ( yc ) from the free-surface:

                       y_c = (d + \frac{L}{2} ) \\\\y_c = (43 + \frac{8}{2} ) \\\\y_c = 47 m

- Now we can calculate the resultant hydro static force ( F ) acting on the window. The specific gravity of fluid ( water ) is γ = 9.8KN/m^3.

                         F = ( 9.8 ) * ( 47 )* ( 8 )^2\\\\F = 29479KN

Note: The values given in the posted question seem unreasonable. I have assumed values in order of convenience. However, the procedure of solving the problem remains exactly the same.

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