A 0.850 kg mass is placed on a
1 answer:
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The radius of the sphere is r=5.15 cm=0.0515 m, and its surface is given by
So the total charge on the surface of the sphere is, using the charge density
:
The electrostatic force between the sphere and the point charge is:
where
ke is the Coulomb's constant
Q is the charge on the sphere
is the point charge
r is their separation
Re-arranging the equation, we can find the separation between the sphere and the point charge:
So the total charge on the surface of the sphere is, using the charge density
The electrostatic force between the sphere and the point charge is:
where
ke is the Coulomb's constant
Q is the charge on the sphere
r is their separation
Re-arranging the equation, we can find the separation between the sphere and the point charge:
Check the attached file for the answer.
Answer:
The intensity of the net electric field will:
Explanation:
Here we need first find the electric field due to the first charge at the midway point.
The electric field equation is given by:
Where:
- k is Coulomb's constant
- q(1) is 20.00 μC or 20*10⁻⁶ C
- d is the distance from q1 to the midpoint (d=10.0 cm)
So, we will have:
The direction of E1 is to the right of the midpoint.
Now, the second electric field is:
The direction of E2 is to the right of the midpoint because the second charge is negative.
Finally, the intensity of the net electric field will:
I hope it helps you!