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neonofarm [45]
3 years ago
11

The area of a circle is equal to the area of a square measuring 5 centimeters on each side find the radius of the circle

Mathematics
1 answer:
Gre4nikov [31]3 years ago
4 0
The area os the square is 25 cm sq so the radius of the circle should be about 2.82 cm
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Edward has several missing assignments in his math class with a total of 274 problems to complete. His goal is to complete 4 pro
brilliants [131]
Part a I am pretty sure it is a pattern so 4 plus 2 is 6, 6 plus 3 is nine and then 9 plus 4 is 13 Then 13 plus 5 is 18

Answer is 18

In part b he will not finish his work he has to get to 274 and he only gets to about 50 something
Hope this helps
5 0
3 years ago
Plz help multiply and divide one step​
emmainna [20.7K]

Answer:

The value if y is -7

hope it helps you

4 0
2 years ago
Read 2 more answers
Help me Please..
Fittoniya [83]
Just general definitons:

a TRInomial has 3 terms (tri means three)
a BInomial has 2 terms (bi means two)
a MONOmial has 1 term (mono means one)

the degree is the highest exponent found in the algebraic expression

so they should be pretty easy to solve with that information, but just in case:

1. trinomial, degree of 4
2. binomial, degree of 3
3. monomial, degree of 2

for the final question, all you have to do is plug in 2 for x, so

(2)^2 - 2(2) + 1

4 - 4 + 1

so the answer is 1
7 0
3 years ago
A triangle has side lengths of 9 in, 13 in, and 20 in. What is the measurement of this triangle's largest angle?
Rama09 [41]

1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :

     i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.

      ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

       a^{2}=b ^{2}+c ^{2}-2bc(cosA)

2.

20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA)

400=81+169-234(cosA)   150=-234(cosA)

cosA=150/-234= -0.641

3. m(A) = Arccos(-0.641)≈130°,

4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc

6 0
3 years ago
Read 2 more answers
The hours of daylight, y, in Utica in days x from January 1, 2013 can be modeled by the equation y = 2.89sin(0.0145x-1.40) + 10.
Pie

Answer:

9.3 hours

Step-by-step explanation:

Given

y = 2.89\sin(0.0145x-1.40) + 10.99.

Required

Hours of sunlight on Feb 21, 2013

First, calculate the number of days from Jan 1, 2013 to Feb 21, 2013

days = 52

So:

x = 52

So, we have:

y = 2.89\sin(0.0145x-1.40) + 10.99.

y = 2.89\sin(0.0145*52-1.40) + 10.99.

y = 2.89\sin(0.754-1.40) + 10.99.

y = 2.89\sin(-0.646) + 10.99.

y = 2.89*-0.6020 + 10.99.

y = -1.740 + 10.99.

y = 9.25

<em></em>y = 9.3<em> --- approximated</em>

8 0
3 years ago
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