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3 years ago

8.3 kg, 1.7 Kg/cm3 -> ? cm3

Chemistry

1 answer:

Gre4nikov [31]3 years ago

6 0

Answer:

4.9 cm³

Explanation:

Given data:

Mass value = 8.3 kg

Density = 1.7 kg/cm³

Volume = ?

Solution;

In given question from the units we got to know that the mass and density value is given and we have to calculate the volume.

Thus, we will apply density formula.

Density = mass/ volume

d = m/v

1.7 kg/cm³ = 8.3 kg/ v

v = 8.3 kg/ 1.7 kg/cm³

v = 4.9 cm³

Thus, the volume is 4.9 cm³.

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how do i solve these equations using proust's law? we haven't gone over balancing chem equations in class and our teacher doesn'

kow [346]

Answer:

Explanation:

Ok so Proust's Law, better known as the Law of Definite Proportions, states that the components of a compound always exist in a fixed ratio. This means that it does not matter what the source of the components are nor the coefficients in front of them. The ratio your teacher is referring to is most likely mass percent/ percent composition. This ratio is the amount of the component over the amount of the entire compound times 100%.

*I am not very familiar with this law so please do with my answers what you will :)*

7.)

First, you want to find the percent composition (aka mass composition) of Na in NaCl.

45.89 g Na
--------------------- x 100% = 39.3%
116.89 g NaCl

So, there must be 39.3% sodium in NaCl. You can find how much chlorine is in NaCl by subtracting that percent by 100 (to find the percent composition of chlorine) then multiplying it by the mass.

100% - 39.3% = 60.7%

60.7% / 100 = 0.0607

116.89 g NaCl x 0.0607 = 70.91 g Cl₂

You could also just subtract the mass of sodium from the mass of sodium chloride to find the mass of chlorine.

116.89 g NaCl - 45.89 g Na = 71 g Cl₂

8.)

10.57 g Mg + 6.96 g O₂ = 17.53 g MgO

6.96 g O₂
--------------------- x 100% = 39.7% O₂
17.53 g MgO

9.)

6.46 g Pb = 1 g O₂

68.54 g Pb = 28.76 g O₂

68.54 g Pb / 28.76 g O₂ = 2.83 g ≠ 6.46 g

No, the two samples are not the same because the proportion of lead to oxygen is not the same for both samples. In the first sample, there is 6.46 g lead for every oxygen. In the second sample, there is 2.38 g lead for every oxygen.

6 0

1 year ago

What is the mass of a sample of iron that has had 300.0 j applied to it and heats up from 20.0 degrees Celsius to 40.0 degrees C

yuradex [85]

Answer:

The mass of a sample of iron that has had 300 J applied to it and heats up from 20 degrees Celsius to 40 degrees Celsius is 32.61 grams.

Explanation:

Calorimetry is the measurement and calculation of the measurement of heat changes exchanged by a body or a system produced in physical and chemical processes.

The sensible heat of a body is the amount of heat received or transferred by a body to produce a change in temperature but without a change in physical state.

The sensible heat in a constant pressure is calculated by:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c, and where ΔT is the temperature variation (ΔT=Tfinal - Tinitial)

In this case:

Q= 300 J

c= 0.46 $\frac{J}{g*C}$

m= ?
Tfinal= 40 C
Tinitial= 20 C

Replacing:

300 J= 0.46 $\frac{J}{g*C}$ * m* (40 - 20) C

Solving:

300 J= 0.46 $\frac{J}{g*C}$ * m* 20 C

$m=\frac{300 J}{0.46 \frac{J}{g*C} * 20 C}$

m= 32.61 g

4 0

2 years ago

4Fe + 302 → 2Fe2O3

frez [133]

Answer:

2 -> O and Fe

Explanation:

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2 years ago

Which of the following is the best definition of an independent variable

Soloha48 [4]

Answer:

that one

Explanation:

<h2>esssszzzzjijfc</h2>

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3 years ago

Lionel places red blood cells in a beaker of pure water, and then he observes their

scZoUnD [109]

Answer:

The red blood cells will burst

Explanation:

When the red blood cells are placed in pure water, they will gain water by osmosis, swell and finally burst due to their weak cell membranes. This process is referred to as hemolysis.

7 0

2 years ago