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Inessa05 [86]
4 years ago
12

The energy collected from the tiles cannot be stored as kinetic energy. What energy transformation is occurring within the tiles

Physics
2 answers:
Evgen [1.6K]4 years ago
8 0

Answer:

In the most classical notation, we have two types of energy, Kinetic energy, is that one that the objects in the movement have usually is written as K = (m/2)*v^2

And the other type is the potential energy, this energy is the one "stored" that can be transformed into kinetic energy later, for example, an object that is lifted from the ground and remains in your hand has no kinetic energy, but it has potential energy.

Then, the energy in the tyles is stored as "potential energy", of course, this can be more specific, assuming that the tiles are solar tiles, the conversion is from thermal energy or radiation to potential energy (even more specific, if the energy is being stored in a battery, the transformation would be from thermal energy to chemical energy)

In-s [12.5K]4 years ago
4 0

Answer:

potential energy

Explanation:

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Explanation:

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3 years ago
A 25 kg child plays on a swing having support ropes that are 2.20 m long. A friend pulls her back until the ropes are 42◦ from t
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Answer:

A) P.E = 138.44 J

B) The velocity of swing at bottom, v = 3.33 m/s

C) The work done, W = -138.44 J

Explanation:

Given,

The mass of the child, m = 25 Kg

The length of the swing rope, L = 2.2 m

The angle of the swing to the vertical position, ∅ = 42°

A) The potential energy at the initial position ∅ = 42° is given by the relation

                                P.E = mgh joule

Considering h  = 0 for the vertical position

The h at ∅ = 42° is  h = L (1 - cos∅)

                               P.E = mgL (1 - cos∅)

Substituting the given values in the above equation

                               P.E = 25 x 9.8 x 2.2 (1 - cos42°)

                                      = 138.44 J

The potential energy for the child just as she is released, compared to the potential energy at the bottom of the swing is, P.E = 138.44 J

B) The velocity of the swing at the bottom.

At bottom of the swing the P.E is completely transformed into the K.E

                  ∴                 K.E = P.E

                                     1/2 mv² = 138.44

                                     1/2 x 25 x v² 138.44

                                            v² = 11.0752

                                             v = 3.33 m/s

The velocity of the swing at the bottom is, v = 3.33 m/s

C) The work done by the tension in the rope from initial position to the bottom

             Tension on string, T = Force acting on the swing, F

                      W=L\int\limits^0_\phi{F} \, d \phi

                             =L\int\limits^0_\phi{mg.sin \phi} \, d \phi

                            = -Lmg[cos\phi]_{42}^{0}

                            = - 2.2 x 25 x 9.8 [cos0 - cos 42°]

                            = - 138.44 J

The negative sign in the in energy is that the work done is towards the gravitational force of attraction.

The work done by the tension in the ropes as the child swings from the initial position to the bottom of the swing, W = - 138.44 J

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Answer:

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Explanation:

Since the diameter of one long piece of thin wire is too thin to be measured by a metre ruler, you can wind it multiple times and push it side by side to get a length you can measure.

For example, if you wound it around 20 times and the total length of 20 diameters of the wire side-by-side is 2.0 cm, one winding, which is the diameter would be 2.0cm ÷ 20 = 0.10cm or 1mm.

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Answer:

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Explanation:

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