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Travka [436]
2 years ago
6

A student conducts an experimenting to test how the temperature of a ball affects its bounce height. The same ball is used for e

ach test, and the ball is dropped from the same height each time what is the independent variable
Physics
2 answers:
telo118 [61]2 years ago
8 0
Independent variable = the thing you change.
Here the independent variable is the temperature of the ball
uysha [10]2 years ago
3 0

the independent variable is what you're testing or changing in an experiment, so the answer is the temperature of the ball when its dropped.

i hope that helped <3

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What should be angle between force and displacement to get the maximum work​
Bas_tet [7]

Answer:

0°

Explanation:

The angle between force and displacement should be 0° in order to get the maximum work done.

 

 Work done  = Force  x dcosФ°  

  Ф is the angle between force and displacement

When Ф is zero, the maximum work done is attained

When Ф is 90, the minimum work is done, in fact, work done is 0

3 0
3 years ago
Which of the following represents an upright image? <br> A. -do<br> B. +m<br> C. -m<br> D. +do
Tom [10]

Answer:

B. +m

Explanation:

The magnification of an image is defined as the ratio between the size of the image and of the object:

m = \frac{y'}{y}

where we have

y' = size of the image

y = size of the object

There are two possible situations:

- When m is positive, y' has same sign as y: this means that the image image is upright

- When m is negative, y' has opposite sign to y: this means that the image is upside down

Therefore, the correct option representing an upright image is

B. +m

5 0
3 years ago
The distance traveled by an object can be modeled by the equation d = ut + 0.5at2 where d = distance, u = initial velocity, t =
Taya2010 [7]
We are given with the expression d = ut + 0.5 at^2 and is asked to express the equation in terms of a. First, we transpose ut to the left side, then we multiply to the equation and divide lastly the resulting equation by t^2. The final expression becomes a = 2(d-ut)/t^2.
8 0
3 years ago
What is the fundamental frequency (in Hz) of a 0.632 m long tube, open at both ends, on a day when the speed of sound is 344 m/s
Greeley [361]

Answer:

f=272.15Hz

Explanation:

Given data

Length of tube L=0.632 m

Speed of sound v=344 m/s

To find

Fundamental frequency f

Solution

The fundamental frequency of the tube can be given as:

f=\frac{v}{2L}\\ f=\frac{344m/s}{2(0.632m)}\\ f=272.15Hz

4 0
4 years ago
4. A car, initially traveling east with a speed of
PilotLPTM [1.2K]

Answer:

150 m

Explanation:

Given,

u=5m/s

a=2m/s2

t=10s

v=?

s=?

Now,

v=u+at

=5+2×10

=5+20

=25m/s

So,

s=u+v/2×t

=5+25/2×10

=30/2×10

=15×10

=150m

5 0
3 years ago
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