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3 years ago

What happens to the gravitational force between two masses when the distance between the masses is doubled?

Physics

1 answer:

vovangra [49]3 years ago

6 0

Answer:

It decreases by a factor of 4

Explanation:

The gravitational force between two masses is given by

$F=\frac{Gm_1 m_2}{r^2}$

where

G is the gravitational constant

m1, m2 are the two masses

r is the separation between the two masses

In this problem, the distance between the masses is doubled, so

r' = 2r

Substituting into the equation, we see that the new force is

$F'=\frac{Gm_1 m_2}{(2r)^2}=\frac{1}{4}\frac{Gm_1m_2}{r^2})\frac{F}{4}$

So, the force decreases by a factor of 4.

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Two resistors A and B are arranged in series in one branch of a parallel arrangement. The other branch contains a single resisto

Ganezh [65]

Answer:

Explanation:

A and B are in series , Total resistance = Ra + Rb

This resistance is in parallel with single resistor C

Equivalent resistance Re = Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )]

Now this combination is in series in single resistance D .

Total resistance = Rd + Re

= Rd + { Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )] }

5 0

3 years ago

Spiderman has a mass of 80 kg. He knows his webbing will break if it is exposed to a 200 N force. What is the maximum height he

likoan [24]

Answer:

This depends on the writers

if they want they can make spiderman deny the laws of nature

8 0

3 years ago

The output voltage of a voltage amplifier has been found to decrease by 20% when a load resistance of 1 k is connected. What is

yKpoI14uk [10]

We use the voltage division problem between the load resistance, amplifier output resistance as

$V_{out} = V_{amlifire} \times \frac{R_{load} }{R_{load} + R_{out} }$ .

Here, $V_{out}$ is the output voltage, $V_{amlifire}$ is the amplifier voltage, $R_{load}$ is the load resistance and $R_{out}$ is the amplifier output resistance.

Therefore,

$1-\frac{20}{100} = \frac{1 \ k\Omega }{1 \ k\Omega +R_{out} } \\\\ R_{out} = \frac{1 \ k\Omega }{0.8} -1 \ k\Omega =1250 \Omega -1000 \Omega =250 \Omega$ .

Thus, the amplifier output resistance is $250 \ \Omega$ .

4 0

3 years ago

Does a race car driver need a faster reaction time then someone driving in a school zone explain your answer

rosijanka [135]

Answer:
Yes, the race car driver needs a faster reaction time than someone driving in a school zone.

Explanation.
For the sake of argument, let us consider
(i) a person driving at 35 mph in a school zone (as a normal driver);
(ii) a person driving at 60 mph in a school zone (as a racing driver).

Suppose a blind pedestrian crosses the road 0.1 miles (about 500 feet) in front of the driver.
The time before the normal driver hits the pedestrian is
(0.1 /35)*3600 = 10.3 seconds.
The time before the racing driver hits the pedestrian is
(0.1/60)*3600 = 6 seconds.

Because a reaction time of 6 seconds may be insufficient to avoid hitting the pedestrian, the racing driver needs a faster reaction time than the normal driver.

6 0

4 years ago

If the mass of a material is 48 grams and the volume of the material is 8 cm^3, what would the density of the material be?

iris [78.8K]

Density’s is mass by volume
So mass is 48 grams
Volume is 8cm^3
There is no need to convert units as they are same
So 48/8 gives you 6
So your answe should be 6g/cm^3 or 6gcm^-3

4 0

3 years ago