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2 years ago

Identify two fields where physical quantities are used in motion calculations

Physics

1 answer:

larisa86 [58]2 years ago

4 0

The two fields were physical quantities are used in motion calculations are length and mass with time.

The physical quantity in a field is referred as every point in a particular space time.

<h3>How physical quantities are used in motion calculations?</h3>

If we consider an object, the physical property of the object is considered as physical quantity and to measure that object is known as units. The Physical quantity can be classified as elemental physical quantity and derived physical quantity. Length, mass, time, etc.. are elemental physical quantity, momentum, density, acceleration, etc... are derived physical quantity. Only for charge and temperature the physical quantity will be less than zero.

Length, mass and time are the physical quantities used in motion calculations.

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A flat loop of wire consisting of a single turn of cross-sectional area 7.10 cm2 is perpendicular to a magnetic field that incre

MAVERICK [17]

<span>From Ohm's law. V = IR. Where R = 2 Ohms. To calculate the induced current I; We need to calculate the electromotive force or voltage, V. From Faraday's law induced EMF = (The rate of change of magnetic flux density x Area)/ (changein time). Or EMF = BA/t. Where B = Bf - Bi. And BA = Bf* A - Bi* A. Bf = 2.00 and Bi = 0.500 and t = 0.93s and the area, A = 7.1 cm^2 is 0.000071 m^2. 2 So Emf = 2.00 (0.000071) - 0.500(0.000071) /(0.93) = 1.0654 * 10^(-4)/ 0.93 = 1.1415 * 10^(-4). Substituting into ohms law, we have, I = (1.1415 * 10^(-4)) / 2 = 0.57075 * 10^(-4)</span>

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3 years ago

A 10cm long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire

soldi70 [24.7K]

Answer:

a) $v=4.0m/s$

b) $B=2.958T$

Explanation:

From the question we are told that:

Wire Length $l=10cm=>0.10m$

Resistance $R=0.35$

Force $F=1.0N$

Power $P=4.0W$

Generally the equation for Power is mathematically given by

$P=Fv$

Therefore

$v=\frac{P}{F}$

$v=\frac{4.0}{1.0}$

$v=4.0m/s$

Generally the equation for Magnetic Field is mathematically given by

$B=\frac{\sqrt{PR}}{vl}$

$B=\frac{\sqrt{4*0.35}}{4*0.10}$

$B=2.958T$

5 0

3 years ago

A 9800-N automobile is pushed along a level road by four students who apply a total forward force of 600 N. Neglecting friction,

Alexandra [31]

Answer:

c). $a = 0.60 m/s^2$

Explanation:

As we know that weight of the automobile is given here

so weight = mass times gravity

$W = mg$

$9800 = m(9.8)$

$m = 1000 kg$

now from Newton's law

$F = ma$

$600 = 1000 a$

$a = \frac{600}{1000}$

$a = 0.60 m/s^2$

4 0

3 years ago

You are driving your car, and the traffic light ahead turns red. you apply the brakes for 2.26 s, and the velocity of the car de

Lorico [155]

Let the initial velocity of the car be u.

Final velocity of the car (v) = 5.43 m/s

deceleration (a) = - 2.78 m/s^2

Time taken (t) = 2.26 s

Using the first equation of motion:

v = u + at

u = v - at

$u = 5.43 - (-2.78 \times 2.26)$

u = 5.43 + 6.28

u = 11.71 m/s

Let the car's displacement be x.

Using second equation of motion:

$x = ut + \frac{1}{2}at^2$

$x = 11.71 \times 2.26 - \frac{1}{2} \times 2.78 \times 2.26^2$

x = 26.4646 - 7.0995

x = 19.3651 meters

Hence, the displacement of the car is 19.36 meters

6 0

3 years ago

When developing a question for a scientific inquiry, the question will ideally A. identify variables. B. be measurable. C.

Rus_ich [418]

When developing a question for a scientific inquiry, the question will ideally D. all of these.
When it comes to a scientific inquiry, it is important that the question identify variables, be measurable, and not just simply ask why. There have to be a couple of variables, you have to be able to measure the results, and to prove them, supported by evidence.

6 0

3 years ago

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Identify two fields where physical quantities are used in motion calculations​

Identify two fields where physical quantities are used in motion calculations