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Answer:
The entropy of a substance can be obtained by measuring the heat required to raise the temperature a given amount, using a reversible process . The standard molar entropy, So, is the entropy of 1 mole of a substance in its standard state, at 1 atm of pressure. (Below are listed tips)
- At absolute zero (0 K), the entropy of a pure, perfect crystal is zero.
- The entropy of a substance can be obtained by measuring the heat required to raise the temperature a given amount, using a reversible process.
- The standard molar entropy, So, is the entropy of 1 mole of a substance in its standard state, at 1 atm of pressure.
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Answer:
Okay?.......................
Answer: Option (B) is the correct answer.
Explanation:
When the book was at the shelf, it had only potential energy as potential energy is the energy possessed due to the position of an object.
Therefore, when the book falls from the book shelf it gains kinetic energy as kinetic energy is the energy possessed due to the motion of an object.
Thus, when the books is falling from the top shelf then the motion of book increases therefore, we can conclude that the potential energy decreases as kinetic energy increases.
The chemical formula of hydrocortisone valerate is C26H38O6. First, we determine the molar mass of the substance by adding up all the products of the number of atoms and the molar mass of atoms as shown below.
molar mass = 26(12) + 38(1) + 6(16) = 446 g/mol
Since, there are 26 atoms of carbon in each molecule, the mass of carbon in each mole is
mass of carbon = (26)(12) = 312
Obtaining the percent by mass of carbon,
% by mass of carbon = (312/446) x 100 %
= 69.955%
Thus, the percent by mass of carbon in hydrocortisone valerate is approximately 69.96%.
Answer:
Ammonia is limiting reactant
Amount of oxygen left = 0.035 mol
Explanation:
Masa of ammonia = 2.00 g
Mass of oxygen = 4.00 g
Which is limiting reactant = ?
Balance chemical equation:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
Number of moles of ammonia:
Number of moles = mass/molar mass
Number of moles = 2.00 g/ 17 g/mol
Number of moles = 0.12 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 4.00 g/ 32 g/mol
Number of moles = 0.125 mol
Now we will compare the moles of ammonia and oxygen with water and nitrogen.
NH₃ : N₂
4 : 2
0.12 : 2/4×0.12 = 0.06
NH₃ : H₂O
4 : 6
0.12 : 6/4×0.12 = 0.18
O₂ : N₂
3 : 2
0.125 : 2/3×0.125 = 0.08
O₂ : H₂O
3 : 6
0.125 : 6/3×0.125 = 0.25
The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.
Amount of oxygen left:
NH₃ : O₂
4 : 3
0.12 : 3/4×0.12= 0.09
Amount of oxygen react = 0.09 mol
Amount of oxygen left = 0.125 - 0.09 = 0.035 mol