Answer:
3
I would like to understand the temperature at which a substance will vaporize when dissolved in a liquid. I have researched this online for hours, but haven't found a conclusive answer. Is it the boiling point of the dissolved substance? I'm attempting to find the temperature at which caffeine vaporizes when dissolved in water or other vegetable glycerin.
Explanation:
I hope this helps a little bit
Answer:
20.2 kJ
Explanation:
Based on the information in the reaction, the amount of heat released per mole of Na₂O₂ (the molar enthalpy) is calculated as follows:
126 kJ / 2 mol = 63 kJ/mol Na₂O₂
The number of moles in 25.0g of Na₂O₂ must be calculated using the molecular weight of Na₂O₂ (77.978 g/mol):
(25.0 g)/(77.978 g/mol) = 0.32060 mol Na₂O₂
Thus, the heat released will be:
(63 kJ/mol)(0.32060 mol) = 20.2 kJ
It would be +3
Since the number of protons and electrons must be equal in an atom for it to be neutral, if it looses electrons it becomes positively charged ion and if it gains electrons it becomes negatively charged ion.
If anything you would use a protractor but that’s not a answer.... so I would pick whatever relates to a protractor
Answer: Stimulus
Explanation: The definition of Stimulus is "a thing or event that evokes a specific functional reaction in an organ or tissue," according to the Oxford Dictionary. So the book dropping and causing a noise is an example of a stimulus.
