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kozerog [31]
2 years ago
10

Help asap i need help

Chemistry
1 answer:
zalisa [80]2 years ago
3 0

Answer:

from producers to consumers

Explanation:

Energy is transferred between organisms in food webs from producers to consumers. The energy is used by organisms to carry out complex tasks. The vast majority of energy that exists in food webs originates from the sun and is converted (transformed) into chemical energy by the process of photosynthesis in plants

Short answer, don't know but i'm sure the answer is up here

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Jeremy bought a new truck for $32,000. The value of the truck after t years can be represented by the formula V = 32,000(.8)t. H
Irina18 [472]

Your answer is  $20,480.

Hope this Helped!

<h3>Also here is the explanation: </h3><h3>https://www.symbolab.com/solver/equation-calculator/x%3D32000%5Cleft(.8%5Cright)%5E%7B2%7D</h3>
7 0
3 years ago
the daily dose of ampicillin for the treatment of an ear infection is 115 mg/kg of body weight. what is the daily dose for a 43-
Lorico [155]
M=43lb = 19,5kg

If 115mg --------- is for --------- 1kg
                             so
    x        ---------- is for --------- 19,5kg

x = 19,5kg * 115mg / 1kg
x = 2242,5 mg
6 0
2 years ago
Read 2 more answers
How are the following aspects of a reaction affected by the addition of a catalyst? 1) activation energy of the reverse reaction
snow_tiger [21]

These are four questions and four answers.

Answers:

1) activation energy of the reverse reaction

     b. Decreased

2) Rate of the forward reaction

    a. Increased

3) Rate of the reverse reaction

    a. Increased

4) Activation energy of the forward reaction

    b. decreased

Explanation:

<em>Activarion energy</em> is the energy required by the reactants to form the intermediate transition state and become products.

<em>Catalysts</em> are substances that change the path of the chemical reactions, lowering the activation energy, and thus speeding up the rate of the reactions, since the products can reach the new lower activation energy faster.

The equilibrium reactions are the chemical process in which two reactions, the <em>forward and the reverese reactions</em>, occur simultaneously and at the same rate.  The equlibrium reactions may be represented by:

  • A ⇄ B

Where A → B is the direct or forward reaction, and A ← B is the reverse reaction (note the inversed arrow, from right to left).

For the direct reaction A represents the reactants and B represents the products. On the other hand, B represents the reactants and A represents the reactants of the reverse reaction and A. This, is A is the reactant of the forward reaction and the product of the reverse reaction, while B is the reactant of the reverse reaction and the product of the forward reaction.

Since, <em>the addition of a catalyst</em> lowers the activation energy of the process, the new activation energy is lower for both the forward and the reverse reaction, meaning that:

1. <em>The activation energy of the reverse reaction is decreased</em> (option b. of the first question)

2.<em> The rate of the forward reaction is increased</em> (option a. of the second question)

3. <em>The rate of the reverse reaction is increased</em> (option a. of the third question).

4. <em>Activation energy of the forward reaction is decreased</em> (option b. of the fourth question).

In summary, the addition of a catalyst decreases the activation energy for both forward and reverse reactions, and increases the rate of both forward and reverse reactions.

3 0
3 years ago
Read 2 more answers
YO I NEED HELP!!!! APEX PLEASE
podryga [215]
B is the correct answer for it
8 0
3 years ago
Read 2 more answers
In the first 22.0 s of this reaction, the concentration of HBr dropped from 0.590 M to 0.465 M . Calculate the average rate of t
jolli1 [7]

Answer:

The average rate is 2.84 X 10⁻³ Ms⁻¹

Explanation:

Average rate = -0.5*Δ[HBr]/Δt

given;

[HBr]₁ = 0.590 M

[HBr]₂ = 0.465 M

Δ[HBr] = [HBr]₂  - [HBr]₁ = 0.465 M - 0.590 M = -0.125 M

Δt Change in time = 22.0 s

Average rate = -0.5*Δ[HBr]/Δt

Average rate = - 0.5(-0.125)/22

Average rate = 0.00284 Ms⁻¹ = 2.84 X 10⁻³ Ms⁻¹

Therefore, the average rate is 2.84 X 10⁻³ Ms⁻¹

8 0
3 years ago
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