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satela [25.4K]
2 years ago
9

State your claim. Make sure your claim fully explains how you can distinguish between materials that appear similar. HELPPPPPP M

EEEEE PLZZZZZZZZ!!!!!!!!!!!!!!!!!!!!!

Chemistry
2 answers:
snow_lady [41]2 years ago
7 0
The right one is darker than the left
asambeis [7]2 years ago
5 0
The material on the right is a darker shade than the one on the left. Also the one on the right also is less of a block and a little more shagged
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The total mass of the atmosphere is about 5.00 x 1018 kg. How many moles each of air, O2, and CO2 are present in the atmosphere?
n200080 [17]

<u>Answer:</u> The moles of oxygen and carbon dioxide in air is 3.63\times 10^{19}mol and 7.18\times 10^{16}mol respectively

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of atmosphere = 5.00\times 10^{18}kg=5.00\times 10^{21}g

Average molar mass of atmosphere = 28.96 g/mol

Putting values in above equation, we get:

\text{Moles of atmosphere}=\frac{5.00\times 10^{21}g}{28.96g/mol}=1.73\times 10^{20}mol

We know that:

Percent of oxygen in air = 21 %

Percent of carbon dioxide in air = 0.0415 %

Moles of oxygen in air = \frac{21}{100}\times 1.73\times 10^{20}=3.63\times 10^{19}mol

Moles of carbon dioxide in air = \frac{0.0415}{100}\times 1.73\times 10^{20}=7.18\times 10^{16}mol

Hence, the moles of oxygen and carbon dioxide in air is 3.63\times 10^{19}mol and 7.18\times 10^{16}mol respectively

6 0
3 years ago
Determination of the chemical composition of the atmospheres of the planets is carried out most effectively by what type of stud
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a helium filled balloon has a volume of 208 l and it contains 9.95 moles of gas. if the pressure of the balloon is 1.26 atm dete
daser333 [38]
To determine the temperature of the gas, we need to assume ideal gas to use the equation PV=nRT where P represents the pressure, V is the volume, n is the number of moles, T is the temperature and R is the universal gas constant. We calculate as follows:

PV = nRT
T = PV / nR

T = (1.26 atm) ( 208 L ) / 0.08205 L-atm/mol-K ( 9.95 mol )
T = 321.02 K

Hope this answers the question.
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3 years ago
When sugar glucose, C6H12O6, is burned with air, carbon dioxide and water vapor are produced. Write the balanced equation and ca
Alex Ar [27]
6CO2 + 6H2O YOU JUST ADD THEM TOGETHER
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Soil that are light in color have a great amount of humus in<br> them. True or False
GaryK [48]

Answer:

please the answer Is false

6 0
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