pH is referred to as the scale to describe the hydronium ion concentration of a
solution. It is used to measure the acidity or basicity of a solution. pH of an acidic solution is less than 7, a neutral solution is 7, and a basic solution is greater than 7.
pH can be calculated using the formula:
![pH = - log [H_{3}O^{+}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-%20log%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%20%20)
Given the pH of solution is 3.2.
Finding out the concentration of hydronium ion from pH.
![pH = - log[H_{3}O^{+}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-%20log%5BH_%7B3%7DO%5E%7B%2B%7D%5D)
![3.2 = - log [H_{3}O^{+}]](https://tex.z-dn.net/?f=%203.2%20%3D%20-%20log%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%20%20)
![[H_{3}O^{+}] = 10^{-3.2}](https://tex.z-dn.net/?f=%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-3.2%7D%20%20%20%20)
![[H_{3}O^{+}] = 6.3 * 10^{-4} M](https://tex.z-dn.net/?f=%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%20%20%206.3%20%2A%2010%5E%7B-4%7D%20M%20%20)
Therefore, the hydronium ion concetration of the solution is 
I think it is b sorry if wrong
Answer:
300 mL
Explanation:
the unit formula of calcium phosphate is Ca3(PO4)2
molar mass of Ca3(PO4)2 = (3×40 + 2×31 + 8×16) g/mol = 310 g/mol
n = m/M = 35 g/(310 g/mol)
c = n/V
V = n/c = [35 g/(310 g/mol)]/0.375 mol/L
V = 0.30 L = 300 mL
no. The metal would be the hottest