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Anastasy [175]
2 years ago
11

Plzzz help me find slope

Mathematics
2 answers:
lidiya [134]2 years ago
7 0
Slope is “rise over run” or “up over across.”  The points you are given are (x,y), which means “across, then up”.  So you just need to subtract the second y from the first, and the second x from the first.  

In the first problem, you have (0,0) and (6,7), or think of them as (x1, y1) and (x2, y2).  You just need to find the two differences and divide (slope can be negative).

For problem #1, it is (7-0)/(6-0), which is the same as 7/6 because any number minus 0 is itself.

Use this method for the others and you will have your answers.

NemiM [27]2 years ago
4 0
Slope is y2 - y1/ x2-x1 so # 1 would be 7-0/6-0 or 7/6
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Samantha deposit 300 in an account that earns an annual interest rate of 2.5 after nine months she computes the simple interest.
antiseptic1488 [7]

Answer:

She is doing a mistake of calculating interest after 9 months in place of after 12 months.

Step-by-step explanation:

Samantha deposit $300 in an account that earns an annual interest rate of 2.5%.

Now, Samantha after nine months of deposit computes the simple interest.

She is doing a mistake of calculating interest after 9 months in place of after 12 months.

The calculation of interest should be on a yearly basis (i.e. 12 months) as the interest rate is 2.5% per year. (Answer)

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3 years ago
What is the volume of a<br> cube that has one side of ||<br> cm?
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8 0
2 years ago
Read 2 more answers
What is 5/12 of 2/5 i need help
Marianna [84]

Answer:10/60

If need to  simply it is 1/6.

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5 0
3 years ago
A 15-ft ladder leans against a wall. The lower end of the ladder is being pulled away from the wall at the rate of 1.5 ft/sec. L
Aleks [24]

Answer:

The top of the ladder is sliding down at a rate of 2 feet per second.

Step-by-step explanation:

Refer the image for the diagram. Consider \Delta ABC as right angle triangle. Values of length of one side and hypotenuse is given. Value of another side is not known. So applying Pythagoras theorem,

\left ( AB \right )^{2}+\left ( BC \right )^{2}=\left ( AC \right )^{2}

From the given data, L=15\:ft=AC, y=9\:ft=AB and x=BC

Substituting the values,  

\therefore \left ( 9 \right )^{2}+\left ( x \right )^{2}=\left ( 15 \right )^{2}

\therefore 81+x^{2}=225

\therefore x^{2}=225-81

\therefore x^{2}=144

\therefore \sqrt{x^{2}}=\sqrt{144}

\therefore x=\pm 12

Since length can never be negative, so x= 12.

Now to calculate \dfrac{dy}{dt} again consider following equation,  

\left ( y \right )^{2}+\left ( x \right )^{2}=\left ( l \right )^{2}

Differentiate both sides of the equation with respect to t,  

\dfrac{d}{dt}\left(y^2+x^2\right)=\dfrac{d}{dt}\left(l^2\right)

Applying sum rule of derivative,

\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(l^2\right)

\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(225\right)

Applying power rule of derivative,  

2y\dfrac{dy}{dt}+2x\dfrac{dx}{dt}=0

Simplifying,  

y\dfrac{dy}{dt}+x\dfrac{dx}{dt}=0

Substituting the values,  

9\dfrac{dy}{dt}+12\times1.5=0

9\dfrac{dy}{dt}+18=0

Subtracting both sides by 18,

9\dfrac{dy}{dt}=-18

Dividing both sides by 9,

\dfrac{dy}{dt}= - 2

Here, negative indicates that the ladder is sliding in downward direction.  

\therefore \dfrac{dy}{dt}= 2\:\dfrac{ft}{sec}

7 0
3 years ago
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