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Anastasy [175]
2 years ago
11

Plzzz help me find slope

Mathematics
2 answers:
lidiya [134]2 years ago
7 0
Slope is “rise over run” or “up over across.”  The points you are given are (x,y), which means “across, then up”.  So you just need to subtract the second y from the first, and the second x from the first.  

In the first problem, you have (0,0) and (6,7), or think of them as (x1, y1) and (x2, y2).  You just need to find the two differences and divide (slope can be negative).

For problem #1, it is (7-0)/(6-0), which is the same as 7/6 because any number minus 0 is itself.

Use this method for the others and you will have your answers.

NemiM [27]2 years ago
4 0
Slope is y2 - y1/ x2-x1 so # 1 would be 7-0/6-0 or 7/6
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Ashley opened a lemonade stand on her street. It costs her $12.50 to buy the supplies each day, and she sells lemonade for $2.50
nasty-shy [4]

Answer:

75

Step-by-step explanation:

Subtract sales - expenses

200 - 12.5 = 187.5

2.5x = 187.5

Divide by 2.5 on both sides

187.5/2.5

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6 0
3 years ago
PLEASE HELP ME!
lawyer [7]
At the beining, he has 76
that is at x=0
y=mx+76

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100=2m+76
minus 76 both sides
24=2m
divide both sides by 2
12=m

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3 years ago
A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula
Ilia_Sergeevich [38]

Answer: A. A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}

              B. A'(5) = 1.76 cm/s

Step-by-step explanation: <u>Rate</u> <u>of</u> <u>change</u> measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

A=\pi.r^{2}

So to find the rate of the area:

\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}

\frac{dA}{dr} =2.\pi.r

Using r(t)=3-\frac{363}{(t+11)^{2}}

\frac{dr}{dt}=\frac{726}{(t+11)^{3}}

Then

\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]

\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}

Multipying and simplifying:

\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}

The rate at which the area is increasing is given by expression A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}.

B. At t = 5, rate is:

A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}

A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}

A'(5)=\frac{2408693760\pi}{4294967296}

A'(5)=1.76268

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

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