For
|a|<b
assume
-b<a<b
so
add 5 to both side
|-2-8x|<66
assume
-66<-2-8x<66
add 2 to both sides
-64<-8x<68
divide everyboy by -8, don't forget to flip sign
8>x>-8.5
-8.5<x<8
the solution is all numbers between -8.5 and 8, not including -8.5 and 8
in interval notation: (-8.5,8)
or
S={x|-8.5<x<8}
9x^2+t+25=(ax+b)^2
9x^2+t+25=a^2*x^2+2abx+b^2 so
a^2=9 so a=3
b^2=25 so b=5 then
t=2ab using a and b from above
t=2*3*5=30
So the missing term is 30x
Answer:
Here is the ans...hope it helps:)
-3 and 3, both three away from 0
★ QUADRATIC RESOLUTION ★
Roots of the given equation will be imaginary because it's discriminant is less than 0 and hence it'll yield imaginary solutions
D < 0
b² - 4ac < 0
4² - 4 ( 5 ) < 0
16 - 20 < 0
-4 < 0
Hence it's character is stated above
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
