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stepladder [879]
3 years ago
11

Your class hopes to collect at least 325 cans of food for the annual food drive. There were 132 cans donated the first week and

146 more the second week. a. Write an inequality that describes this situation. Let c represent the number of cans of food that must be collected by the end of the third week for your class to meet or surpass your goal. b. How many cans are needed to meet or surpass your goal? 132 + 146 + c > 325; c > 47 132 + 146 + c ≥ 325; c ≥ 47 132 + 146 + c ≥ 325; c ≤ 603 132 + 146 + 325 ≥ c; c ≥ 603
Mathematics
1 answer:
beks73 [17]3 years ago
4 0
132 + 146 + c should be greater than or equal to 325, and c should be greater than or equal to 47.
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55 points see attachment below
Ludmilka [50]

Answer:

  f(3) = -20

Step-by-step explanation:

To find the value of a function, substitute the number for the variable and do the arithmetic.

  f(x) = -2x^2 +x -5 . . . . . . given

  f(3) = -2(3^2) +(3) -5 . . . . function value for x = 3

  f(3) = -2(9) +3 -5 = -18 +3 -5

  f(3) = -20

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Express each number as a single-digit integer times a power of 10.<br> 24,755,183,009,522
jek_recluse [69]
2 to the 12th power should be correct
7 0
3 years ago
If you pay for $25.00 for purchase which includes 11% sales tax. how much is the sales tax?
Delvig [45]
Since it includes 11% sales tax, this means that (purchase)+11% of (purchase)=25.00. Since 11% = 0.11 by multiplying it by 1/100, we have 1*purchase+0.11*purchase=1.11*purchase=25.00. Dividing both sides by 1.11, we get around 22.73 as the original purchase. This means that the difference between the purchase price and the total price is the sales tax, which is around 2.27 dollars.

Feel free to ask further questions!
5 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST: What is the local minimum value of the function g(x)=x^4-5x^2+4? (Round answer to the nearest hundredth)
IrinaK [193]

Answer:

Step-by-step explanation:

you can find where the first derivative is 0 to find the critical points

g'(x) = ( x^4 -5x^2 +4)' = 4x³-10x

g'(x) =0, make y =0 to find find where g'(x) is 0

4x³-10x =0 , factor 2x

2x(2x²-5)= 0 , each factor must be 0

2x= 0, so x= 0

2x²-5 =0, so x = ±√5/2

we now have 3 critical points -√5/2, 0, and √5/2

make intervals (-∞, -√5/2), (-√5/2, 0) , (0, √5/2) and (√5/2, +∞)

pick a point to test on each interval: -2, -1, 1 and 2 for example, and

calculate g'(x) = 4x³-10x at those points

for x= -2 we have 4(-2)³-10(-2) = -12 , negative number, decrease

for x= -1 we have 4(-1)³-10(-1) =6, positive number, increase

for x= 1 we have 4(1)³-10(1) = -6, negative number, decrease

for x= 2 we have 4(2)³-10(2) = 12, positive number, increase

we went from a decrease to an increase on intervals (-∞, -√5/2), (-√5/2, 0) so x= - √5/2 ≈ -1.58 is a minimum

we went from a decrease to an increase on intervals (0, √5/2), (√5/2, +∞) so

x= √5/2 ≈ 1.58 is a minimum as well

4 0
3 years ago
Lena says that and are like terms. Is she correct? Why or why not? A. No, because the same variables are not raised to the same
qwelly [4]

Answer:

D because of the question

8 0
3 years ago
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