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stepladder [879]
4 years ago
11

Your class hopes to collect at least 325 cans of food for the annual food drive. There were 132 cans donated the first week and

146 more the second week. a. Write an inequality that describes this situation. Let c represent the number of cans of food that must be collected by the end of the third week for your class to meet or surpass your goal. b. How many cans are needed to meet or surpass your goal? 132 + 146 + c > 325; c > 47 132 + 146 + c ≥ 325; c ≥ 47 132 + 146 + c ≥ 325; c ≤ 603 132 + 146 + 325 ≥ c; c ≥ 603
Mathematics
1 answer:
beks73 [17]4 years ago
4 0
132 + 146 + c should be greater than or equal to 325, and c should be greater than or equal to 47.
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(a) Complete the table of values for y = 6 - 4x.<br><br> Please help ❤️
shutvik [7]

<u>Answer:</u>

\boxed{\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}}

<u>Step-by-step explanation:</u>

Given equation to us is :-

\implies y = 6 - 4x

So , here we can put different values of x in order to get different values of y .

Initial table given to us is ,

\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & & & 2&&-6 \\\cline{1-6}\end{tabular}

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>:</u><u>-</u>

\implies y = 6 - 4x \\\\\implies y = 6 -4(-1) \\\\\implies y = 6 + 4 \\\\\red{\bf\implies y = 10}

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

\implies y = 6 - 4x \\\\\implies y = 6-4(0) \\\\\implies y = 6 - 0 \\\\\pink{\bf\implies y = 6 }

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u>

\implies y = 6-4x \\\\\implies y = 6 - 4(2) \\\\\implies y = 6 - 8 \\\\\blue{\bf\implies y = (-2)}

<u>Hence </u><u>the</u><u> </u><u>final</u><u> </u><u>table</u><u> </u><u>would</u><u> </u><u>be</u><u> </u><u>:</u><u>-</u><u> </u>

\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}

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3 years ago
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aivan3 [116]

Answer:

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Step-by-step explanation:

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