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Whitepunk [10]
3 years ago
11

A high-mass star has more "fuel" than a low-mass star. which lives longer? why?

Physics
1 answer:
forsale [732]3 years ago
6 0
Low mass lives long .
Because High mass loss his energy sooner and it will die . so low mass longer live
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Light passes through the following structures in which order
VladimirAG [237]

Question:The complete question can be found in the attached image below.

Answer: Light passes through the eyes through the following correct order

cornea--> aqueous humor---> lens -------------------->vitreous humor.

Explanation:

The CORNEA is a dome shaped structure that covers the anterior part of the eye. Light rays passes through it first as it enters the eye. The AQUEOUS HUMOR is located anterior to the lens which nourishes the lens and helps to maintain intraocular pressure. Light rays pass through it to the LENS. The lens is a clear structure inside the eye that focuses light rays onto the retina. The light rays passes from lens to the VITREOUS HUMOR before reaching the retina. vitreous humor is a jelly-like substance that fills the center of the eye. I hope this helps, thanks

3 0
3 years ago
The smallest scale of the following is
Llana [10]

Answer:

B) 1:100

Explanation:

this explanation is actually simple.

you can see this problem as a simple comparation if you move for example

1:10

if you move 1 cm you are going to move 10cm  in the other side usually is used for planes in architecture or sizing issues, so, if the scale need to be grater, that is if is necessary to increase the number inthe right side in this case 10 cm to 100cm it is because in 100 the resolution is better.

you can see this problem as a fraction

1/10 or 1/1000

4 0
4 years ago
Se colocan tres objetos, muy cerca uno del otro, dos al mismo tiempo. Cuando se juntan los objetos A y B, se repelen. Cuando se
docker41 [41]

Answer:

Los objetos A y C tienen cargas del mismo signo (opcion a)

Explanation:

Hay dos tipos de cargas : cargas positivas y cargas negativas.

La Ley de Coulomb dice que la fuerza electrostática entre dos cargas puntuales es proporcional al producto de las cargas e inversamente proporcional al cuadrado de la distancia que las separa, y tiene la dirección de la línea que las une y se cumple que:

  • La fuerza ejercida sobre una carga apunta hacia la otra cuando las dos tienen distinto signo (fuerza atractiva).
  • El sentido de la fuerza se dirige hacia el lado opuesto de la carga cuando ambas tienen el mismo signo (fuerza repulsiva).

Es decir que las cargas de igual signo se repelen, mientras que las de diferente signo se atraen.

Entonces, si se juntan los objetos A y B y se repelen significa que la carga es del mismo signo.

Cuando se acercan los objetos B y C, se repelen. Entonces significa que posee carga de igual signo.

Por lo que podes concluir que <u><em>los objetos A y C tienen cargas del mismo signo (opcion a)</em></u>

8 0
3 years ago
Astronomy can best be described as a/an
Mars2501 [29]
Astronomy can best be described as a/an .  A<span>. study of objects beyond earths atmosphere", although the subject of astronomy can be much more complicated</span>
3 0
3 years ago
An 1120 kg car traveling at 17 m/s is brought to a stop while skidding 40 m. Calculate the work done on the car by friction forc
sergij07 [2.7K]

Answer:

Approximately (-1.6 \times 10^{5}\; \rm J) (assuming that the car was on level ground.)

Explanation:

When an object of mass m is moving at a speed of v, the kinetic energy of that object would be (1/2) \, m \cdot v^{2}.

Initial kinetic energy of the car:

\begin{aligned}&\frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2}\times 1120\; \rm kg \times (17\; \rm m \cdot s^{-1})^{2} \\ &\approx 1.6\times 10^{5}\; \rm J \end{aligned}.

After the car comes to a stop, the kinetic energy of this car would be 0\; \rm J because the car would not be moving.

Change to the kinetic energy of the car: \text{Final KE} - \text{Initial KE} = -1.6 \times 10^{5}\; \rm J.

If the car is traveling on level ground, friction would be the only force that contributed to this energy change. Hence:

\text{Work of friction} = \text{Energy change} = -1.6\times 10^{5}\; \rm J.

The value of the work that friction did is negative. The reason is that at any instant before the car comes to a stop, friction would be exactly opposite to the direction of the movement of the car.

The work of a force on an object is the dot product of that force and the displacement of that object. The dot product of two vectors of opposite directions is negative. Hence, in this question, the work that friction did on the car would be negative because the friction vector would be opposite to the movement of the car.

6 0
3 years ago
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