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sladkih [1.3K]
3 years ago
10

A wrench 0.500 m long is applied to a nut with a force of 80.0 N. Because of the cramped space, the force must be exerted upward

at an angle of 60.0° with respect to a line from the bolt through the end of the wrench. How much torque is applied to the nut?
1
14.2 N·m
34.6 N·m
20.0 N·m
11.8 N·m
4.56 N·m
Physics
1 answer:
riadik2000 [5.3K]3 years ago
7 0

Answer:

Torque, \tau=34.6\ N.m

Explanation:

It is given that,

Length of the wrench, l = 0.5 m

Force acting on the wrench, F = 80 N

The force is acting upward at an angle of 60.0° with respect to a line from the bolt through the end of the wrench. We need to find the torque is applied to the nut. We know that torque acting on an object is equal to the cross product of force and distance. It is given by :

\tau=Fr\ sin\theta

\tau=80\times 0.5\ sin(60)

\tau=34.6\ N.m

So, the torque is applied to the nut is 34.6 N.m. Hence, this is the required solution.

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On substituting the given values, we get

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3 years ago
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Answer:

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Explain resolution of Force​
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3 years ago
Two identical resistors are connected in parallel across a 26-V battery, which supplies them with a total power of 7.1 W. While
Gnom [1K]

Answer:

A) R = 190.42 Ω

B) P = 5.325 W

Explanation:

We are given;

Total power;P_tot = 7.1 W

Voltage;V = 26 V

A)We are told that while the battery is still connected, one of the resistors is heated, so that its resistance doubles.

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Now, formula for power is;

P = IV

Thus, since power is doubled, we have;

P = 2(IV)

Now, formula for current is; I = V/R

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Making R the subject, we have;

R = 2V²/P

In this question, P is p_total = 7.1 W

Thus;

R = (2 × 26²)/7.1

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B) Now, the resistance of the resistors are R and 2R.

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P = V²/R

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8 0
4 years ago
What is the resistance at 20°C of a 2.0-meter length of tungsten wire with a cross-sectional area of 7.9 10^-7
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Answer:

1.4 * 10 ^-1 Ω

Explanation:

Hi,

For this question, we gotta use the formula

R = pL/A

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The resistivity of tungsten is 5.60 * 10^-8 at 20°C

By plugging the values, we get:

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