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jeka57 [31]
2 years ago
9

200 N of force is applied to the pedals of a bike has output force of 450 N what is the mechanical advantage of the bike

Physics
1 answer:
enot [183]2 years ago
4 0

Answer:

2.25 N

Explanation:

The formula for mechanical advantage is:

Mechanical \ Advantage = \frac{F_o}{F_i}

F_o stands for output force and F_i stands for input force.

We can plug in the given forces into the equation:

Mechanical \ Advantage = \frac{450\ N}{200\ N}=2.25 \ N

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The final velocity of the tool is 107.4 m/s

Explanation:

We can solve this problem by using the principle of conservation of energy.

In fact, if air resistance is negligible, the total mechanical energy of the tool is conserved during the fall, so we can write:

K_i + U_i = K_f + U_f

where

K_i = 0 is the kinetic energy of the tool at the top (zero since it is at rest)

U_i = mgh is the gravitational potential energy of the tool at the top, where

m is the mass of the tool

g is the acceleration of gravity

h is the heigth of the tool

K_f = \frac{1}{2}mv^2 is the kinetic energy of the tool just before hitting the ground, where

v is the final speed of the tool

U_f = 0 is the gravitational potential energy of the tool at the bottom (zero since the height is zero)

Re-arranging the equation,

mgh=\frac{1}{2}mv^2

where we have

g=9.8 m/s^2\\h=588 m

And solving for v,

v=\sqrt{2gh}=\sqrt{2(9.8)(588)}=107.4 m/s

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3 years ago
What can be used to describe the quantitative data
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6 0
3 years ago
A semi-trailer is coasting downhill along a mountain highway when its brakes fail. The driver pulls onto a runaway truck ramp th
aleksklad [387]

<u>Answer:</u>

The velocity is 30.279 m/s

<u>Explanation</u>:

Consider the initial speed of the semi-trailer be v

Then, initial kinetic energy = \frac{1}{2} mv^2

According to question, the semi-trailer coast along a ramp, which is inclined at an angle of 170, and to a distance of 160m to stop

Change in vertical position =h=160 \times \sin 17^{\circ}-0= 46.779m

Final potential energy of semitrailer = mgh

Applying principle of conservation of energy,

\frac{1}{2} mv^2 = mgh

Solving for v, we get v^2 = 2gh = 2*9.8*46.779 = 916.8684

v^2 = 916.8684

v = 30.279 m/s

Therefore, the velocity is 30.279 m/s

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3 years ago
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