200 N of force is applied to the pedals of a bike has output force of 450 N what is the mechanical advantage of the bike

Physics

1 answer:

enot [183]2 years ago

4 0

Answer:

2.25 N

Explanation:

The formula for mechanical advantage is:

$Mechanical \ Advantage = \frac{F_o}{F_i}$

$F_o$ stands for output force and $F_i$ stands for input force.

We can plug in the given forces into the equation:

$Mechanical \ Advantage = \frac{450\ N}{200\ N}=2.25 \ N$

You might be interested in

A pendulum on earth swings with angular frequency ω. On an unknown planet, it swings with angular frequency ω/ 4. The accelerati

Afina-wow [57]

Answer:

g / 16

Explanation:

T = 2π $\sqrt{\frac{l}{g} }$

angular frequency ω = 2π /T

= $\sqrt{\frac{g}{l} }$

ω₁ /ω₂ = $\sqrt{\frac{g_1}{g_2} }$

Putting the values

ω₁ = ω , ω₂ = ω / 4

ω₁ /ω₂ = 4

4 = $\sqrt{\frac{g}{g_2} }$

g₂ = g / 16

option d is correct.

6 0

3 years ago

Ow much charge flows from a 12.0 v battery when it is connected across a completely discharged 18.0 μf capacitor

Trava [24]

The equation Q=CV (Charge = product of Capacitance and potential difference) tells us that the maximum charge that can be stored on a capacitor is equal to the product of it's capacitance and the potential difference across it. In this case the potential difference across the capacitor will be 12.0V (assuming circuit resistance is negligable) and it has a capacitance of 18.0μf or 18.0x10^-6f, therefore charge equals (18.0x10^-6)x12=2.16x10^-4C (Coulombs).

5 0

2 years ago

An object is launched with an initial speed of 30 m/s at an angle of 60° above the horizontal . What is the maximum height reach

matrenka [14]

Answer:

H = 34.43 m

Explanation:

Given that,

Initial speed of the object, u = 30 m/s

The angle of projection, $\theta=60^{\circ}$