Answer:
Explanation:
Given
Ship A velocity is 40 mph and is traveling 35 west of north
Therefore in 2 hours it will travel 
thus its position vector after two hours is

similarly B travels with 20 mph and in 2 hours
![=20\times 2=40 miles Its position vector[tex]r_B=40sin80\hat{i}+40cos80\hat{j}](https://tex.z-dn.net/?f=%3D20%5Ctimes%202%3D40%20miles%20%3C%2Fp%3E%3Cp%3EIts%20position%20vector%5Btex%5Dr_B%3D40sin80%5Chat%7Bi%7D%2B40cos80%5Chat%7Bj%7D)
Thus distance between A and B is



Velocity of A

Velocity of B

Velocity of A w.r.t B


Refractor, It's a refractor-esque telescope
Answer:
1.04 s
Explanation:
The computation is shown below:
As we know that
t = t' × 1 ÷ (√(1 - (v/c)^2)
here
v = 0.5c
t = 1.20 -s
So,
1.20 = t' × 1 ÷ (√(1 - (0.5/c)^2)
1.20 = t' × 1 ÷ (√(1 - (0.5)^2)
1.20 = t' ÷ √0.75
1.20 = t' ÷ 0.866
t' = 0.866 × 1.20
= 1.04 s
The above formula should be applied
So the initial velocity is 15 m/s, the final velocity is 0 since it's at a complete stop and time is 10 seconds. Therefore:

Therefore, the acceleration is -1.5 m/s^2. The reason it's negative is due to the fact that the vector is going against it's original movement since it's decelerating.
Answer:
Belgium
France
Luxembourg
Explanation:
These are the ones that are in the High Productivity chart, but not in the HDI chart