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Kipish [7]
3 years ago
6

Consider the following arrangement with a frictionless/massless pulley. Determine the force F required to move block A if the co

efficient of static friction between block A and the floor is 0.35 and the coefficient of static friction between block A and block B is 0.25
Physics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer: The free - body diagrams for blocks A and B. frictionless surface by a constant horizontal force F = 100 N. Find the tension in the cord between the 5 kg and 10 kg blocks. The string that attaches it to the block of mass M2 passes over a frictionless pulley of negligible mass. The coefficient of kinetic friction Hk between M.

Explanation: Hope this helped :)

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3 years ago
A 0.23 kg mass at the end of a spring oscillates 2.0 times per second with an amplitude of 0.15 m
charle [14.2K]

Answer:

A) v = 1.885 m/s

B) v = 0.39 m/s

C) E = 0.03 J

D) x(t) = (0.15m)\cos(2\pi (2.0Hz)t)

Explanation:

Part A

We will use the conservation of energy to find the speed at equilibrium.

K_{eq} + U_{eq} = K_A + U_A\\\frac{1}{2}mv^2 + 0 = 0 + \frac{1}{2}kA^2\\v = \sqrt{\frac{k}{m}}A

where \omega = \sqrt{k/m} and \omega = 2\pi f

Therefore,

v = 2\pi f A = 2(3.14)(2)(0.15) = 1.885~m/s

Part B

The conservation of energy will be used again.

K_1 + U_1 = K_2 + U_2\\\frac{1}{2}mv^2 + \frac{1}{2}kx^2 = \frac{1}{2}kA^2\\mv^2 + kx^2 = kA^2\\(0.23)v^2 + k(0.10)^2 = k(0.15)^2\\v^2 = \frac{k(0.15)^2-(0.10)^2}{0.23}\\v = \sqrt{0.054k}

where k = \omega^2 m = (2\pi f)^2 m = 2(3.14)(2)(0.23) = 2.89

Therefore, v = 0.39 m/s.

Part C

Total energy of the system is equal to the potential energy at amplitude.

E = \frac{1}{2}kA^2 = \frac{1}{2}(2.89)(0.15)^2 = 0.03~J

Part D

The general equation of motion in simple harmonic motion is

x(t) = A\cos(\omega t + \phi)\\x(t) = (0.15m)\cos(2\pi (2.0Hz)t + \phi)

where \phi is the phase angle to be determined by the initial conditions. In this case, the initial condition is that at t = 0, x is maximum. Therefore,

x(t) = (0.15m)\cos(2\pi (2.0Hz)t)

5 0
4 years ago
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