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tankabanditka [31]
3 years ago
5

To make a 1.0L dilute of 0.5M from a stock solution of 12M, how much solution will be needed?

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
6 0

Answer:

V_{concentrated}=0.042L=4.2mL

Explanation:

Hello,

In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:

M_{diluted}V_{diluted}=M_{concentrated}V_{concentrated}

Clearly, the concentrated solution is 12M and the diluted solution is 0.5 M, thus, the volume of the concentrated solution we should take is:

V_{concentrated}=\frac{M_{diluted}V_{diluted}}{M_{concentrated}} =\frac{0.5M*1.0L}{12M}\\ \\V_{concentrated}=0.042L=4.2mL

Best regards.

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First, we have to get how many grams of C & H & O in the compound:
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- the mass of H atom on H2O = mass of H2O*molar mass of H / molar mass of H2O
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An empty container weighs 80.21 g. it is filled with 20.14 mL of an unknown liquid, and the total weight of the container and li
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1.242 g/mL

Explanation:

Step 1: Given data

Mass of the empty container (m₁): 80.21 g

Mass of the filled container (m₂): 105.22 g

Volume of the unknown liquid (V): 20.14 mL

Step 2: Calculate the mass of the liquid

The mass of the liquid is equal to the difference between the mass of the filled container and the mass of the empty container.

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Step 3: Calculate the density of the unknown liquid

The density of the liquid is equal to its mass divided by its volume.

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