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weeeeeb [17]
2 years ago
10

Calculate the percent mass of sugar in mountain dew: The total mass of the mountain dew solution is 300g and there are 231 g of

sugar in this solution.
a. 0.77 %
b. 1.2 %
c. 77 %
d. none of the above
Chemistry
1 answer:
s2008m [1.1K]2 years ago
4 0

Answer:

c. 77 %

Explanation:

Percent mass (% mass) of solute = mass of solute/mass of solution × 100

According to this question, a mountain dew solution weighing 300grams contains 231 g of sugar. This means that:

% mass of sugar = 231g/300g × 100

% mass of sugar = 0.77 × 100

% mass of sugar = 77%.

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prohojiy [21]

Explanation:

FeSO _{4} + \: KOH \: →K _{2}SO _{4} \:  +  \: Fe(OH) _{2}

5 0
2 years ago
onsider the following reaction: CaCN2 + 3 H2O → CaCO3 + 2 NH3 105.0 g CaCN2 and 78.0 g H2O are reacted. Assuming 100% efficiency
mestny [16]

Answer : The excess reactant is, H_2O

The leftover amount of excess reagent is, 7.2 grams.

Solution : Given,

Mass of CaCN_2 = 105.0 g

Mass of H_2O = 78.0 g

Molar mass of CaCN_2 = 80.11 g/mole

Molar mass of H_2O = 18 g/mole

Molar mass of CaCO_3 = 100.09 g/mole

First we have to calculate the moles of CaCN_2 and H_2O.

\text{ Moles of }CaCN_2=\frac{\text{ Mass of }CaCN_2}{\text{ Molar mass of }CaCN_2}=\frac{105.0g}{80.11g/mole}=1.31moles

\text{ Moles of }H_2O=\frac{\text{ Mass of }H_2O}{\text{ Molar mass of }H_2O}=\frac{78.0g}{18g/mole}=4.33moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3

From the balanced reaction we conclude that

As, 1 mole of CaCN_2 react with 3 mole of H_2O

So, 1.31 moles of CaCN_2 react with 1.31\times 3=3.93 moles of H_2O

From this we conclude that, H_2O is an excess reagent because the given moles are greater than the required moles and CaCN_2 is a limiting reagent and it limits the formation of product.

Left moles of excess reactant = 4.33 - 3.93 = 0.4 moles

Now we have to calculate the mass of excess reactant.

\text{ Mass of excess reactant}=\text{ Moles of excess reactant}\times \text{ Molar mass of excess reactant}(H_2O)

\text{ Mass of excess reactant}=(0.4moles)\times (18g/mole)=7.2g

Thus, the leftover amount of excess reagent is, 7.2 grams.

8 0
3 years ago
A mushroom grows a wide stalk:
Ganezh [65]
Bro mushrooms are pretty elite ngl
8 0
3 years ago
A solution that has a large amount of dissolved solute is called
kvasek [131]

Answer: It is an unsaturated solution

Explanation: This is because it has more solute than a normal solution.

6 0
2 years ago
can a light object that was hit with a small force accelerate as rapidly as a heavier object hit with a big force? why or why no
Tcecarenko [31]

The acceleration is defined by force divided by the mass of the object. So, When the smaller object is hit by a small force, it can produce equal acceleration which is same as that of the bigger body hit with large force.

<h3><u>Explanation:</u></h3>

Force is defined as the product of the mass of the body its applied to and the acceleration of the body in the direction of the force. So acceleration is force divided by the mass of the body.

Let the mass of the smaller body be m and that of the larger body be M.

The smaller force applied on the smaller body be f and the larger force applied on the larger body be F.

So acceleration of the larger body = F/M.

Acceleration of the smaller body = f/m.

For the accelerations to be same,

F/M = f/m.

Or F/f = M/m.

So when the ratio of the force applied on two bodies is in ratio of their masses, the acceleration becomes equal.

3 0
3 years ago
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