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ziro4ka [17]
3 years ago
6

Describe the role of earth's water system in the rock cycle

Chemistry
1 answer:
Oxana [17]3 years ago
7 0
<span>Erosion by wind or water transports the rock particles and sediments to other sooner or later hitting the ocean.then the rocks form together to make sediment rock! :D</span>
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Which law relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions?
kozerog [31]
Ideal Gas law PV=nRT

P- pressure(atm)
V-volume( liter)
R- gas constant
T- temperature(kelvin)
n - number of moles
6 0
3 years ago
Read 2 more answers
Metals can be highly purified using electrolysis. Which equation best reflects the overall process of purifying copper?
makvit [3.9K]

Answer:

A. Cu^+2(aq)cathode ---> Cu^+2(aq)anode

Explanation:

Electrolysis is the process in which current is passed through a solution thereby causing a chemical change at the anode and cathode. Copper is being purified using electrolysis by using impure copper at the anode and pure copper at the cathode. This pure and impure copper are placed in a copper(ii)sulfate electrolyte solution and dc current is made to pass through it.  The resulting changes at the anode and cathode are given by the equation:

cathode: Cu²⁺  + 2e⁻    ⇒     Cu

anode:    Cu     ⇒       Cu²⁺  + 2e⁻

3 0
4 years ago
Read 2 more answers
Determine the vapor pressure (atm) of rubbing alcohol (isopropanol) at 20.0 °C. The normal boiling point of isopropanol is 82.3
jeyben [28]
Here we apply the Clausius-Clapeyron equation:
ln(P₁/P₂) = ΔH/R x (1/T₂ - 1/T₁)

The normal vapor pressure is 4.24 kPa (P₁)
The boiling point at this pressure is 293 K (P₂)
The heat of vaporization is 39.9 kJ/mol (ΔH)
We need to find the vapor pressure (P₂) at the given temperature 355.3 K (T₂)

ln(4.24/P₂) = 39.9/0.008314 x (1/355.3 - 1/293)
P₂ = 101.2 kPa
8 0
3 years ago
Suppose you have a 2.0 molar solution of sodium hydroxide (naoh), and you need 65 ml of 0.6 molar naoh. how should you make this
nalin [4]

The given molarity of sodium hydroxide solution = 2.0 M

The required concentration of sodium hydroxide is 65 mL of 0.6 M NaOH

Converting 65 mL to L:

65mL*\frac{1L}{1000mL} =0.065L

Calculating the moles of NaOH in the final solution:

0.065L * \frac{0.6 mol}{L} =0.039mol

Finding out the volume of 2.0 M solution taken to prepare the final solution:

0.039 mol * \frac{1L}{2.0mol}=0.0195L*\frac{1000mL}{1L} =19.5mL

Therefore, 19.5 mL of 2.0 M NaOH solution and make it up to 65 mL to prepare 0.6 M NaOH solution.


3 0
3 years ago
Which is TRUE about intermolecular
lbvjy [14]

Answer:

They are Weaker than a chemical

<h2>bond</h2>

corrected by the one in the comment section

5 0
3 years ago
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