Answer:
C) the double bond results in the bypassing of the first oxidation step of the pathway, thereby eliminating one FADH2 product
Explanation:
The beta oxidation of fatty acids is the process by which long chain saturated and unsaturated fatty acids are oxidized to the two-carbon product, acetylCoA.
The beta oxudation of fatty acids occurs in four steps after which the chain length is shortened by 2 with cleavage of an acetylCoA molecule.
The first step involves the oxidation of the fatty acid with introduction of a double bond between C-2 and C-3 of the long carbon chain. This reaction produces FADH2 which donates its electrons to electron carriers in the electron transport chain tomproduce 1.5 moles of ATP. This is the case with saturated fatty acids.
However, in unsaturated fatty acids (which are less reduced than saturated fatty acids) where there is already a double bond innthe molecule, the double bond results in the bypassing of the first oxidation step of the pathway, thereby eliminating one FADH2 product.
This causes a reduction In the number of ATP produced by unsaturated fatty acids when compared to saturated fatty acids.
Answer:
Explanation:
Data:
Actual yield = 16.8 g
Theoretical yield = 49.7 g
Calculation:
Answer:
30.26 grams of N₂O₃
Explanation:
Divide by Avogadro's number. This leaves you with the number of moles. Then, multiply by the molar mass of N₂O₃
Answer:A
Explanation:Binary Fission, meaning ‘getting divided into half’ is a type of asexual reproduction where a single living cell grows twice its size and then splits to form two identical daughter cells, each carrying a copy of the parent cell’s genetic material. Examples of cells that use binary fission for division
Answer:
3.38 moles of O2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
4CH2OH + 5O2 → 4CO2 + 6H2O
From the balanced equation above,
4 moles of CH2OH required 5 moles of O2 for complete combustion.
Finally, we shall determine the number of mole of O2 needed to react with 2.7 moles of CH2OH. This can be obtained as follow:
From the balanced equation above,
4 moles of CH2OH required 5 moles of O2 for complete combustion.
Therefore, 2.7 moles of CH2OH will require = (2.7 × 5)/4 = 3.38 moles of O2 for complete combustion.
Thus, 3.38 moles of O2 is required.
